AQA S3 2007 June — Question 6

Exam BoardAQA
ModuleS3 (Statistics 3)
Year2007
SessionJune
TopicApproximating Binomial to Normal Distribution
TypeDerive binomial mean and variance

6
  1. The random variable \(X\) has a binomial distribution with parameters \(n\) and \(p\).
    1. Prove that \(\mathrm { E } ( X ) = n p\).
    2. Given that \(\mathrm { E } \left( X ^ { 2 } \right) - \mathrm { E } ( X ) = n ( n - 1 ) p ^ { 2 }\), show that \(\operatorname { Var } ( X ) = n p ( 1 - p )\).
    3. Given that \(X\) is found to have a mean of 3 and a variance of 2.97, find values for \(n\) and \(p\).
    4. Hence use a distributional approximation to estimate \(\mathrm { P } ( X > 2 )\).
  2. Dressher is a nationwide chain of stores selling women's clothes. It claims that the probability that a customer who buys clothes from its stores uses a Dressher store card is 0.45 . Assuming this claim to be correct, use a distributional approximation to estimate the probability that, in a random sample of 500 customers who buy clothes from Dressher stores, at least half of them use a Dressher store card.