AQA S2 2009 January — Question 5 13 marks

Exam BoardAQA
ModuleS2 (Statistics 2)
Year2009
SessionJanuary
Marks13
PaperDownload PDF ↗
TopicT-tests (unknown variance)
TypeSingle sample confidence interval t-distribution
DifficultyStandard +0.3 This is a straightforward multi-part question on t-distribution confidence intervals requiring standard manipulations (finding mean from interval, calculating standard error, working backwards to find sample variance) and one reverse lookup in t-tables. All parts follow directly from the confidence interval formula with no novel problem-solving required, making it slightly easier than average.
Spec5.05d Confidence intervals: using normal distribution

5 Jane, who supplies fruit to a jam manufacturer, knows that the weight of fruit in boxes that she sends to the manufacturer can be modelled by a normal distribution with unknown mean, \(\mu\) grams, and unknown standard deviation, \(\sigma\) grams. Jane selects a random sample of 16 boxes and, using the \(t\)-distribution, calculates correctly that a \(98 \%\) confidence interval for \(\mu\) is \(( 70.65,80.35 )\).
    1. Show that the sample mean is 75.5 grams.
    2. Find the width of the confidence interval.
    3. Calculate an estimate of the standard error of the mean.
    4. Hence, or otherwise, show that an unbiased estimate of \(\sigma ^ { 2 }\) is 55.6 , correct to three significant figures.
  1. Jane decides that the width of the \(98 \%\) confidence interval is too large. Construct a \(95 \%\) confidence interval for \(\mu\), based on her sample of 16 boxes.
  2. Jane is informed that the manufacturer would prefer the confidence interval to have a width of at most 5 grams.
    1. Write down a confidence interval for \(\mu\), again based on Jane's sample of 16 boxes, which has a width of 5 grams.
    2. Determine the percentage confidence level for your interval in part (c)(i).

5 Jane, who supplies fruit to a jam manufacturer, knows that the weight of fruit in boxes that she sends to the manufacturer can be modelled by a normal distribution with unknown mean, $\mu$ grams, and unknown standard deviation, $\sigma$ grams.

Jane selects a random sample of 16 boxes and, using the $t$-distribution, calculates correctly that a $98 \%$ confidence interval for $\mu$ is $( 70.65,80.35 )$.
\begin{enumerate}[label=(\alph*)]
\item \begin{enumerate}[label=(\roman*)]
\item Show that the sample mean is 75.5 grams.
\item Find the width of the confidence interval.
\item Calculate an estimate of the standard error of the mean.
\item Hence, or otherwise, show that an unbiased estimate of $\sigma ^ { 2 }$ is 55.6 , correct to three significant figures.
\end{enumerate}\item Jane decides that the width of the $98 \%$ confidence interval is too large.

Construct a $95 \%$ confidence interval for $\mu$, based on her sample of 16 boxes.
\item Jane is informed that the manufacturer would prefer the confidence interval to have a width of at most 5 grams.
\begin{enumerate}[label=(\roman*)]
\item Write down a confidence interval for $\mu$, again based on Jane's sample of 16 boxes, which has a width of 5 grams.
\item Determine the percentage confidence level for your interval in part (c)(i).
\end{enumerate}\end{enumerate}

\hfill \mbox{\textit{AQA S2 2009 Q5 [13]}}