AQA C4 2010 January — Question 6 10 marks

Exam BoardAQA
ModuleC4 (Core Mathematics 4)
Year2010
SessionJanuary
Marks10
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicParametric differentiation
TypeFind tangent equation at parameter
DifficultyModerate -0.3 This is a straightforward multi-part question testing standard C4 parametric differentiation. Part (a) involves routine double-angle formula recall and substitution. Part (b) requires the chain rule dy/dx = (dy/dθ)/(dx/dθ) and finding a tangent equation using given values—all standard textbook techniques with no novel problem-solving required. Slightly easier than average due to the scaffolded structure and explicit guidance.
Spec1.05l Double angle formulae: and compound angle formulae1.07s Parametric and implicit differentiation

6
    1. Express \(\sin 2 \theta\) and \(\cos 2 \theta\) in terms of \(\sin \theta\) and \(\cos \theta\).
    2. Given that \(0 < \theta < \frac { \pi } { 2 }\) and \(\cos \theta = \frac { 3 } { 5 }\), show that \(\sin 2 \theta = \frac { 24 } { 25 }\) and find the value of \(\cos 2 \theta\).
  1. A curve has parametric equations $$x = 3 \sin 2 \theta , \quad y = 4 \cos 2 \theta$$
    1. Find \(\frac { \mathrm { d } y } { \mathrm {~d} x }\) in terms of \(\theta\).
    2. At the point \(P\) on the curve, \(\cos \theta = \frac { 3 } { 5 }\) and \(0 < \theta < \frac { \pi } { 2 }\). Find an equation of the tangent to the curve at the point \(P\).

Question 6:
Part (a)(i)
AnswerMarks Guidance
\(\sin2\theta=2\sin\theta\cos\theta\)B1
\(\cos2\theta=\cos^2\theta-\sin^2\theta\)B1 (2 marks) OE; condone use of \(x\) etc, but variable must be consistent
Part (a)(ii)
AnswerMarks Guidance
\(\sin\theta=\frac{4}{5}\Rightarrow\sin2\theta=2\times\frac{4}{5}\times\frac{3}{5}=\frac{24}{25}\)B1 (1 mark) AG; Use of \(106.26°\ldots\) B0
\(\cos2\theta=\frac{9}{25}-\frac{16}{25}=-\frac{7}{25}\)B1 (2 marks) \(-0.28\)
Part (b)(i)
AnswerMarks Guidance
\(\frac{dx}{d\theta}=6\cos2\theta\quad,\quad\frac{dy}{d\theta}=-8\sin2\theta\)M1 Attempt both derivatives, ie \(p\cos2\theta\), \(q\sin2\theta\)
A1Both correct
\(\frac{dy}{dx}=-\frac{4\sin2\theta}{3\cos2\theta}\) ISWA1 (3 marks) CSO, OE
Part (b)(ii)
AnswerMarks Guidance
\(P\left(\frac{72}{25},-\frac{28}{25}\right)\)B1F \((2.88,-1.12)\)
Gradient \(=-\frac{4}{3}\times-\frac{24}{7}\)M1 Their \(\frac{q\sin2\theta}{p\cos2\theta}\) or \(\frac{p\cos2\theta}{q\sin2\theta}\); must be working with rational numbers
Tangent \(\quad y+\frac{28}{25}=\frac{32}{7}\left(x-\frac{72}{25}\right)\) ISWA1 (3 marks) Any correct form; \(7y=32x-100\); Fractions in simplest form; Equation required
Total: 10 marks
## Question 6:

### Part (a)(i)
| $\sin2\theta=2\sin\theta\cos\theta$ | B1 | |
| $\cos2\theta=\cos^2\theta-\sin^2\theta$ | B1 (2 marks) | OE; condone use of $x$ etc, but variable must be consistent |

### Part (a)(ii)
| $\sin\theta=\frac{4}{5}\Rightarrow\sin2\theta=2\times\frac{4}{5}\times\frac{3}{5}=\frac{24}{25}$ | B1 (1 mark) | AG; Use of $106.26°\ldots$ B0 |
| $\cos2\theta=\frac{9}{25}-\frac{16}{25}=-\frac{7}{25}$ | B1 (2 marks) | $-0.28$ |

### Part (b)(i)
| $\frac{dx}{d\theta}=6\cos2\theta\quad,\quad\frac{dy}{d\theta}=-8\sin2\theta$ | M1 | Attempt both derivatives, ie $p\cos2\theta$, $q\sin2\theta$ |
| | A1 | Both correct |
| $\frac{dy}{dx}=-\frac{4\sin2\theta}{3\cos2\theta}$ ISW | A1 (3 marks) | CSO, OE |

### Part (b)(ii)
| $P\left(\frac{72}{25},-\frac{28}{25}\right)$ | B1F | $(2.88,-1.12)$ |
| Gradient $=-\frac{4}{3}\times-\frac{24}{7}$ | M1 | Their $\frac{q\sin2\theta}{p\cos2\theta}$ **or** $\frac{p\cos2\theta}{q\sin2\theta}$; must be working with rational numbers |
| Tangent $\quad y+\frac{28}{25}=\frac{32}{7}\left(x-\frac{72}{25}\right)$ ISW | A1 (3 marks) | Any correct form; $7y=32x-100$; Fractions in simplest form; Equation required |

**Total: 10 marks**
6
\begin{enumerate}[label=(\alph*)]
\item \begin{enumerate}[label=(\roman*)]
\item Express $\sin 2 \theta$ and $\cos 2 \theta$ in terms of $\sin \theta$ and $\cos \theta$.
\item Given that $0 < \theta < \frac { \pi } { 2 }$ and $\cos \theta = \frac { 3 } { 5 }$, show that $\sin 2 \theta = \frac { 24 } { 25 }$ and find the value of $\cos 2 \theta$.
\end{enumerate}\item A curve has parametric equations

$$x = 3 \sin 2 \theta , \quad y = 4 \cos 2 \theta$$
\begin{enumerate}[label=(\roman*)]
\item Find $\frac { \mathrm { d } y } { \mathrm {~d} x }$ in terms of $\theta$.
\item At the point $P$ on the curve, $\cos \theta = \frac { 3 } { 5 }$ and $0 < \theta < \frac { \pi } { 2 }$. Find an equation of the tangent to the curve at the point $P$.
\end{enumerate}\end{enumerate}

\hfill \mbox{\textit{AQA C4 2010 Q6 [10]}}