Edexcel S1 2003 June — Question 3 10 marks

Exam BoardEdexcel
ModuleS1 (Statistics 1)
Year2003
SessionJune
Marks10
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicBivariate data
TypeCalculate r from raw bivariate data
DifficultyModerate -0.8 This is a routine S1 correlation calculation with coding provided. All summations are given, requiring only substitution into standard formulas for Sxx, Syy, Sxy and r. Part (c) tests understanding that linear coding doesn't affect correlation. Straightforward bookwork with no problem-solving or insight required.
Spec2.02g Calculate mean and standard deviation2.02h Recognize outliers2.05f Pearson correlation coefficient2.05g Hypothesis test using Pearson's r

3. A company owns two petrol stations \(P\) and \(Q\) along a main road. Total daily sales in the same week for \(P ( \pounds p )\) and for \(Q ( \pounds q )\) are summarised in the table below.
\(p\)\(q\)
Monday47605380
Tuesday53954460
Wednesday58404640
Thursday46505450
Friday53654340
Saturday49905550
Sunday43655840
When these data are coded using \(x = \frac { p - 4365 } { 100 }\) and \(y = \frac { q - 4340 } { 100 }\), $$\Sigma x = 48.1 , \Sigma y = 52.8 , \Sigma x ^ { 2 } = 486.44 , \Sigma y ^ { 2 } = 613.22 \text { and } \Sigma x y = 204.95 .$$
  1. Calculate \(S _ { x y } , S _ { x x }\) and \(S _ { y y }\).
  2. Calculate, to 3 significant figures, the value of the product moment correlation coefficient between \(x\) and \(y\).
    1. Write down the value of the product moment correlation coefficient between \(p\) and \(q\).
    2. Give an interpretation of this value.

(a)
AnswerMarks Guidance
\(S_{xx} = 204.95 - \frac{48.1 \times 52.8}{7} = -157.86142\)M1 A1 (awrt −157.9)
\(S_{xx} = 155.92428\)A1 (awrt 155.9)
\(S_{yy} = 214.95714\)A1 (awrt 215.0)
(4 marks)
(b)
AnswerMarks Guidance
\(r = \frac{-157.86142}{\sqrt{155.92428... \times 214.95714}}\)M1 A1 ft
\(= -0.862269\)A1 (awrt −0.862)
(3 marks)
(c)(i)
AnswerMarks
\(-0.862\)B1
(ii)
AnswerMarks Guidance
As sales at on petrol station increases, the other decreases; limited pool of customers; close one garageB1 (2 marks)
(9 marks)
**(a)**
| $S_{xx} = 204.95 - \frac{48.1 \times 52.8}{7} = -157.86142$ | M1 A1 | (awrt −157.9) |
| $S_{xx} = 155.92428$ | A1 | (awrt 155.9) |
| $S_{yy} = 214.95714$ | A1 | (awrt 215.0) |
| | | (4 marks) |

**(b)**
| $r = \frac{-157.86142}{\sqrt{155.92428... \times 214.95714}}$ | M1 A1 ft | |
| $= -0.862269$ | A1 | (awrt −0.862) |
| | | (3 marks) |

**(c)(i)**
| $-0.862$ | B1 | |

**(ii)**
| As sales at on petrol station increases, the other decreases; limited pool of customers; close one garage | B1 | (2 marks) |
| | | (9 marks) |

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3. A company owns two petrol stations $P$ and $Q$ along a main road. Total daily sales in the same week for $P ( \pounds p )$ and for $Q ( \pounds q )$ are summarised in the table below.

\begin{center}
\begin{tabular}{|l|l|l|}
\hline
 & $p$ & $q$ \\
\hline
Monday & 4760 & 5380 \\
\hline
Tuesday & 5395 & 4460 \\
\hline
Wednesday & 5840 & 4640 \\
\hline
Thursday & 4650 & 5450 \\
\hline
Friday & 5365 & 4340 \\
\hline
Saturday & 4990 & 5550 \\
\hline
Sunday & 4365 & 5840 \\
\hline
\end{tabular}
\end{center}

When these data are coded using $x = \frac { p - 4365 } { 100 }$ and $y = \frac { q - 4340 } { 100 }$,

$$\Sigma x = 48.1 , \Sigma y = 52.8 , \Sigma x ^ { 2 } = 486.44 , \Sigma y ^ { 2 } = 613.22 \text { and } \Sigma x y = 204.95 .$$
\begin{enumerate}[label=(\alph*)]
\item Calculate $S _ { x y } , S _ { x x }$ and $S _ { y y }$.
\item Calculate, to 3 significant figures, the value of the product moment correlation coefficient between $x$ and $y$.
\item \begin{enumerate}[label=(\roman*)]
\item Write down the value of the product moment correlation coefficient between $p$ and $q$.
\item Give an interpretation of this value.
\end{enumerate}\end{enumerate}

\hfill \mbox{\textit{Edexcel S1 2003 Q3 [10]}}