CAIE M1 2020 Specimen — Question 7 9 marks

Exam BoardCAIE
ModuleM1 (Mechanics 1)
Year2020
SessionSpecimen
Marks9
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicWork done and energy
TypeConnected particles with pulley
DifficultyStandard +0.3 This is a standard connected particles problem using energy methods. Part (a) requires basic equations of motion with constant acceleration, while part (b) applies work-energy principle with friction - both are routine M1 techniques with straightforward multi-step application but no novel insight required.
Spec3.03o Advanced connected particles: and pulleys6.02b Calculate work: constant force, resolved component6.02i Conservation of energy: mechanical energy principle

7 \includegraphics[max width=\textwidth, alt={}, center]{87b42689-791c-4f4e-a36e-bfae3191ca11-12_244_668_264_701} Two particles \(A\) and \(B\), of masses 0.8 kg and 0.2 kg respectively, are connected by a light inextensible string. Particle \(A\) is placed on a horizontal surface. The string passes over a small smooth pulley \(P\) fixed at the edge of the surface, and \(B\) hangs freely. The horizontal section of the string, \(A P\), is of length 2.5 m (see diagram). The particles are released from rest with both sections of the string taut.
  1. Given that the surface is smooth, find the time taken for \(A\) to reach the pulley.
  2. It is given instead that the surface is rough and that the speed of \(A\) immediately before it reaches the pulley is \(v \mathrm {~m} \mathrm {~s} ^ { - 1 }\). The work done against friction as \(A\) moves from rest to the pulley is 2 J . Use an energy method to find \(v\).

AnswerMarks Guidance
7(a)EITHER Solution 1 \(T = 0.8a\) for \(0 \leq t \leq 0.2a\) \(0.2a - 0.2a = 0.05\text{m}^2\) \(a = 2 - 0.2a\) \(a = 2.5 = [(0.2, 0.8)]\) OR Solution 2 \(T = 0.2a\) \(0.2a = 0.2 + 0.05\) \(a = [-(0 + \sqrt{D})]\) Available marks M1 M1 A1 M1 A1 M1
Question 7(b):
AnswerMarks Guidance
7(b)\(T = 0.2a\) \(0.2a - [(0.2 \times 2) + 0.05]\) \(0.2a - [0.05 \times 0.05]\) \(t = 1.58s\) \(r = 1.58s\) M1M1 A1 A1
Question 7(c):
AnswerMarks Guidance
7(c)MI For applying Newton's 2nd law either to the system as whole or to particles individually Particle B or particle A or the system \(2.5 = (0 + \sqrt{D})\) Allow \(\sqrt{v_D}\) M1 A1
**7(a)** | EITHER Solution 1 $T = 0.8a$ for $0 \leq t \leq 0.2a$ $0.2a - 0.2a = 0.05\text{m}^2$ $a = 2 - 0.2a$ $a = 2.5 = [(0.2, 0.8)]$ OR Solution 2 $T = 0.2a$ $0.2a = 0.2 + 0.05$ $a = [-(0 + \sqrt{D})]$ Available marks | M1 M1 A1 M1 A1 M1 | 

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# Question 7(b):

**7(b)** | $T = 0.2a$ $0.2a - [(0.2 \times 2) + 0.05]$ $0.2a - [0.05 \times 0.05]$ $t = 1.58s$ $r = 1.58s$ | M1M1 A1 A1 | 

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# Question 7(c):

**7(c)** | MI For applying Newton's 2nd law either to the system as whole or to particles individually Particle B or particle A or the system $2.5 = (0 + \sqrt{D})$ Allow $\sqrt{v_D}$ | M1 A1 |
7\\
\includegraphics[max width=\textwidth, alt={}, center]{87b42689-791c-4f4e-a36e-bfae3191ca11-12_244_668_264_701}

Two particles $A$ and $B$, of masses 0.8 kg and 0.2 kg respectively, are connected by a light inextensible string. Particle $A$ is placed on a horizontal surface. The string passes over a small smooth pulley $P$ fixed at the edge of the surface, and $B$ hangs freely. The horizontal section of the string, $A P$, is of length 2.5 m (see diagram). The particles are released from rest with both sections of the string taut.\\
(a) Given that the surface is smooth, find the time taken for $A$ to reach the pulley.\\
(b) It is given instead that the surface is rough and that the speed of $A$ immediately before it reaches the pulley is $v \mathrm {~m} \mathrm {~s} ^ { - 1 }$. The work done against friction as $A$ moves from rest to the pulley is 2 J .

Use an energy method to find $v$.\\

\hfill \mbox{\textit{CAIE M1 2020 Q7 [9]}}