| Exam Board | CAIE |
|---|---|
| Module | M1 (Mechanics 1) |
| Year | 2020 |
| Session | Specimen |
| Marks | 4 |
| Paper | Download PDF ↗ |
| Mark scheme | Download PDF ↗ |
| Topic | SUVAT in 2D & Gravity |
| Type | Vertical projection: max height |
| Difficulty | Easy -1.3 This is a standard textbook SUVAT question asking for maximum height and time of flight for vertical projection under gravity. Both parts use direct application of kinematic equations (v² = u² + 2as for part a, and s = ut + ½at² or symmetry for part b) with no problem-solving or conceptual challenge beyond routine substitution. |
| Spec | 3.02h Motion under gravity: vector form |
| Answer | Marks | Guidance |
|---|---|---|
| 1(a) | 0 – 201 – 208 | M1 |
| 1(b) | 0 – 201 – 10r \(r = 2\) | M1 A1 |
**1(a)** | 0 – 201 – 208 | M1 | For using $s = 2ar$ with $a = 0.05 \text{m}^2$ width = 10 to find $s$, the greatest height
**1(b)** | 0 – 201 – 10r $r = 2$ | M1 A1 | For using $a = 4 + u + v = 1$ u + at $r = 20$; greatest height reached
---1 A particle $P$ is projected vertically upwards with speed $20 \mathrm {~m} \mathrm {~s} ^ { - 1 }$ from a point on the ground.\\
(a) Find the greatest height above the ground reached by $P$.\\
(b) Find the total time from projection until $P$ returns to the ground.\\
\hfill \mbox{\textit{CAIE M1 2020 Q1 [4]}}