12 The gradient function of a curve is given by \(\frac { \mathrm { d } y } { \mathrm {~d} x } = \frac { x ^ { 2 } \sin 2 x } { 2 \cos ^ { 2 } 4 y - 1 }\).
- Find an equation for the curve in the form \(\mathrm { f } ( y ) = g ( x )\).
The curve passes through the point \(\left( \frac { 1 } { 4 } \pi , \frac { 1 } { 12 } \pi \right)\).
- Find the smallest positive value of \(y\) for which \(x = 0\).
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