OCR Further Additional Pure 2018 December — Question 1

Exam BoardOCR
ModuleFurther Additional Pure (Further Additional Pure)
Year2018
SessionDecember
TopicVector Product and Surfaces

1 A surface has equation \(z = x \tan y\) for \(- \frac { 1 } { 2 } \pi < y < \frac { 1 } { 2 } \pi\).
  1. Find
    • \(\frac { \partial z } { \partial x }\),
    • \(\frac { \partial z } { \partial y }\).
    • Find in cartesian form, the equation of the tangent plane to the surface at the point where \(x = 1\) and \(y = \frac { 1 } { 4 } \pi\).