SPS SPS FM Mechanics 2021 January — Question 6

Exam BoardSPS
ModuleSPS FM Mechanics (SPS FM Mechanics)
Year2021
SessionJanuary
TopicCentre of Mass 1

6. \section*{Numerical (calculator) integration is not acceptable in this question.} \begin{figure}[h]
\includegraphics[alt={},max width=\textwidth]{bab18666-3571-4906-ab2f-b85e87c6e8f4-7_538_542_461_831} \captionsetup{labelformat=empty} \caption{Figure 2}
\end{figure} The shaded region \(O A B\) in Figure 2 is bounded by the \(x\)-axis, the line with equation \(x = 4\) and the curve with equation \(y = \frac { 1 } { 4 } ( x - 2 ) ^ { 3 } + 2\). The point \(A\) has coordinates \(( 4,4 )\) and the point \(B\) has coordinates \(( 4,0 )\). A uniform lamina \(L\) has the shape of \(O A B\). The unit of length on both axes is one centimetre. The centre of mass of \(L\) is at the point with coordinates \(( \bar { x } , \bar { y } )\). Given that the area of \(L\) is \(8 \mathrm {~cm} ^ { 2 }\),
  1. show that \(\bar { y } = \frac { 8 } { 7 }\) The lamina is freely suspended from \(A\) and hangs in equilibrium with \(A B\) at an angle \(\theta ^ { \circ }\) to the downward vertical.
  2. Find the value of \(\theta\).