OCR MEI C2 2009 January — Question 12 12 marks

Exam BoardOCR MEI
ModuleC2 (Core Mathematics 2)
Year2009
SessionJanuary
Marks12
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicExponential Functions
TypeLinear transformation to find constants
DifficultyModerate -0.3 This is a standard logarithmic linearization question requiring routine application of log laws (part i), plotting points (part ii), reading gradient and intercept from a graph (part iii), substituting t=0 (part iv), and solving a logarithmic equation (part v). While multi-part with several marks, each step follows a well-practiced procedure with no novel problem-solving required, making it slightly easier than average.
Spec1.06h Logarithmic graphs: reduce y=ax^n and y=kb^x to linear form2.02c Scatter diagrams and regression lines

12 Answer part (ii) of this question on the insert provided. The proposal for a major building project was accepted, but actual construction was delayed. Each year a new estimate of the cost was made. The table shows the estimated cost, \(\pounds y\) million, of the project \(t\) years after the project was first accepted.
Years after proposal accepted \(( t )\)12345
Cost \(( \pounds y\) million \()\)250300360440530
The relationship between \(y\) and \(t\) is modelled by \(y = a b ^ { t }\), where \(a\) and \(b\) are constants.
  1. Show that \(y = a b ^ { t }\) may be written as $$\log _ { 10 } y = \log _ { 10 } a + t \log _ { 10 } b$$
  2. On the insert, complete the table and plot \(\log _ { 10 } y\) against \(t\), drawing by eye a line of best fit.
  3. Use your graph and the results of part (i) to find the values of \(\log _ { 10 } a\) and \(\log _ { 10 } b\) and hence \(a\) and \(b\).
  4. According to this model, what was the estimated cost of the project when it was first accepted?
  5. Find the value of \(t\) given by this model when the estimated cost is \(\pounds 1000\) million. Give your answer rounded to 1 decimal place.

Question 12:
Part i:
AnswerMarks Guidance
Answer/WorkingMarks Guidance
\(\log a + \log(b^t)\) wwwB1 condone omission of base throughout question
clear use of \(\log(b^t) = t\log b\) depB1
Part ii:
AnswerMarks Guidance
Answer/WorkingMarks Guidance
\((2.398),\ 2.477,\ 2.556,\ 2.643,\ 2.724\)T1
points plotted correctly f.t.P1 On correct square
ruled line of best fit f.t.1
Part iii:
AnswerMarks Guidance
Answer/WorkingMarks Guidance
\(\log a = 2.31\) to \(2.33\)M1 ft their intercept
\(a = 204\) to \(214\)A1
\(\log b = 0.08\) approxM1 ft their gradient
\(b = 1.195\) to \(1.215\)A1
Part iv:
AnswerMarks Guidance
Answer/WorkingMarks Guidance
e.g. £210 million dep1 their £\(a\) million
Part v:
AnswerMarks Guidance
Answer/WorkingMarks Guidance
\(\frac{\log 1000 - \text{their intercept}}{\text{their gradient}} \approx \frac{3 - 2.32}{0.08}\)M1
\(= 8.15\) to \(8.85\)A1 or B2 from trials
## Question 12:

### Part i:
| Answer/Working | Marks | Guidance |
|---|---|---|
| $\log a + \log(b^t)$ www | B1 | condone omission of base throughout question |
| clear use of $\log(b^t) = t\log b$ dep | B1 | | **[2]** |

### Part ii:
| Answer/Working | Marks | Guidance |
|---|---|---|
| $(2.398),\ 2.477,\ 2.556,\ 2.643,\ 2.724$ | T1 | |
| points plotted correctly f.t. | P1 | On correct square |
| ruled line of best fit f.t. | 1 | | **[3]** |

### Part iii:
| Answer/Working | Marks | Guidance |
|---|---|---|
| $\log a = 2.31$ to $2.33$ | M1 | ft their intercept |
| $a = 204$ to $214$ | A1 | |
| $\log b = 0.08$ approx | M1 | ft their gradient |
| $b = 1.195$ to $1.215$ | A1 | | **[4]** |

### Part iv:
| Answer/Working | Marks | Guidance |
|---|---|---|
| e.g. £210 million dep | 1 | their £$a$ million | **[1]** |

### Part v:
| Answer/Working | Marks | Guidance |
|---|---|---|
| $\frac{\log 1000 - \text{their intercept}}{\text{their gradient}} \approx \frac{3 - 2.32}{0.08}$ | M1 | |
| $= 8.15$ to $8.85$ | A1 | or B2 from trials | **[2]** |
12 Answer part (ii) of this question on the insert provided.
The proposal for a major building project was accepted, but actual construction was delayed. Each year a new estimate of the cost was made. The table shows the estimated cost, $\pounds y$ million, of the project $t$ years after the project was first accepted.

\begin{center}
\begin{tabular}{ | l | c | c | c | c | c | }
\hline
Years after proposal accepted $( t )$ & 1 & 2 & 3 & 4 & 5 \\
\hline
Cost $( \pounds y$ million $)$ & 250 & 300 & 360 & 440 & 530 \\
\hline
\end{tabular}
\end{center}

The relationship between $y$ and $t$ is modelled by $y = a b ^ { t }$, where $a$ and $b$ are constants.\\
(i) Show that $y = a b ^ { t }$ may be written as

$$\log _ { 10 } y = \log _ { 10 } a + t \log _ { 10 } b$$

(ii) On the insert, complete the table and plot $\log _ { 10 } y$ against $t$, drawing by eye a line of best fit.\\
(iii) Use your graph and the results of part (i) to find the values of $\log _ { 10 } a$ and $\log _ { 10 } b$ and hence $a$ and $b$.\\
(iv) According to this model, what was the estimated cost of the project when it was first accepted?\\
(v) Find the value of $t$ given by this model when the estimated cost is $\pounds 1000$ million. Give your answer rounded to 1 decimal place.

\hfill \mbox{\textit{OCR MEI C2 2009 Q12 [12]}}