OCR MEI Further Extra Pure 2020 November — Question 5 8 marks

Exam BoardOCR MEI
ModuleFurther Extra Pure (Further Extra Pure)
Year2020
SessionNovember
Marks8
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicInvariant lines and eigenvalues and vectors
TypeFind eigenvectors given eigenvalue
DifficultyStandard +0.3 This is a guided multi-part question on eigenvectors with significant scaffolding. Part (a) requires routine verification that a given vector is an eigenvector, (b) is immediate from (a), while (c) and (d) test conceptual understanding of reflections (eigenvectors with eigenvalue 1 lie in the plane, eigenvalue -1 is perpendicular). The geometric interpretation is standard Further Maths content, making this slightly easier than average overall.
Spec4.03a Matrix language: terminology and notation4.03b Matrix operations: addition, multiplication, scalar4.03c Matrix multiplication: properties (associative, not commutative)4.03d Linear transformations 2D: reflection, rotation, enlargement, shear

  1. Show that \(\mathbf { f }\) is also an eigenvector of \(\mathbf { A }\).
  2. State the eigenvalue associated with \(\mathbf { f }\). You are now given that \(\mathbf { A }\) represents a reflection in 3-D space.
  3. Explain the significance of \(\mathbf { e }\) and \(\mathbf { f }\) in relation to the transformation that \(\mathbf { A }\) represents.
  4. State the cartesian equation of the plane of reflection of the transformation represented by \(\mathbf { A }\).

Question 5:
AnswerMarks Guidance
5(b) λ = 1
fB1 2.2a
Completing and correct
conclusion
AnswerMarks Guidance
5(c) Since the e-val of any vector f is 1 then f must be
parallel to (or lie in) the mirror plane.
Since the e-val of e is –1 then e must be perpendicular
AnswerMarks
to the mirror plane.B1
B1
AnswerMarks
[2]2.4
2.4SC1 using the word line
instead of plane
Needs more than invariant
line/line of invariant points
AnswerMarks Guidance
5(d) Since e is the normal to the mirror plane and O must be
in the plane the equation is
1 0 1
     
r. 1 = 0 . 1 =0⇒x+ y+z=0
     
AnswerMarks
1 0 1B1
[1]3.1a
Question 5:
5 | (b) | λ = 1
f | B1 | 2.2a
Completing and correct
conclusion
5 | (c) | Since the e-val of any vector f is 1 then f must be
parallel to (or lie in) the mirror plane.
Since the e-val of e is –1 then e must be perpendicular
to the mirror plane. | B1
B1
[2] | 2.4
2.4 | SC1 using the word line
instead of plane
Needs more than invariant
line/line of invariant points
5 | (d) | Since e is the normal to the mirror plane and O must be
in the plane the equation is
1 0 1
     
r. 1 = 0 . 1 =0⇒x+ y+z=0
     
1 0 1 | B1
[1] | 3.1a
\begin{enumerate}[label=(\alph*)]
\item Show that $\mathbf { f }$ is also an eigenvector of $\mathbf { A }$.
\item State the eigenvalue associated with $\mathbf { f }$.

You are now given that $\mathbf { A }$ represents a reflection in 3-D space.
\item Explain the significance of $\mathbf { e }$ and $\mathbf { f }$ in relation to the transformation that $\mathbf { A }$ represents.
\item State the cartesian equation of the plane of reflection of the transformation represented by $\mathbf { A }$.
\end{enumerate}

\hfill \mbox{\textit{OCR MEI Further Extra Pure 2020 Q5 [8]}}