OCR C4 2008 June — Question 7 8 marks

Exam BoardOCR
ModuleC4 (Core Mathematics 4)
Year2008
SessionJune
Marks8
PaperDownload PDF ↗
TopicDifferential equations
TypeSeparable variables - standard (polynomial/exponential x-side)
DifficultyModerate -0.3 Part (i) is a routine differentiation exercise requiring only the chain rule and knowledge of basic trig derivatives. Part (ii) is a standard separable variables question with straightforward integration of trig functions, though the algebraic manipulation (recognizing sin x tan x = sin²x/cos x leads to sec x after separation) requires some care. Overall slightly easier than average due to being a textbook-style separable DE with no conceptual surprises.
Spec1.05h Reciprocal trig functions: sec, cosec, cot definitions and graphs1.08k Separable differential equations: dy/dx = f(x)g(y)

  1. Show that, if \(y = \operatorname { cosec } x\), then \(\frac { \mathrm { d } y } { \mathrm {~d} x }\) can be expressed as \(- \operatorname { cosec } x \cot x\).
  2. Solve the differential equation $$\frac { \mathrm { d } x } { \mathrm {~d} t } = - \sin x \tan x \cot t$$ given that \(x = \frac { 1 } { 6 } \pi\) when \(t = \frac { 1 } { 2 } \pi\).

(i) Show that, if $y = \operatorname { cosec } x$, then $\frac { \mathrm { d } y } { \mathrm {~d} x }$ can be expressed as $- \operatorname { cosec } x \cot x$.\\
(ii) Solve the differential equation

$$\frac { \mathrm { d } x } { \mathrm {~d} t } = - \sin x \tan x \cot t$$

given that $x = \frac { 1 } { 6 } \pi$ when $t = \frac { 1 } { 2 } \pi$.

\hfill \mbox{\textit{OCR C4 2008 Q7 [8]}}