Edexcel FS1 2023 June — Question 6 13 marks

Exam BoardEdexcel
ModuleFS1 (Further Statistics 1)
Year2023
SessionJune
Marks13
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicProbability Generating Functions
TypeIdentify distribution from PGF
DifficultyChallenging +1.2 This is a Further Maths Statistics question requiring recognition of negative binomial PGF form, standard calculus techniques for expectation/variance, and careful manipulation for part (d). While it requires multiple techniques and is inherently harder than A-level content, the steps are mostly procedural once the distribution is identified. The final part requires some care with index manipulation but follows standard PGF methods.
Spec5.02a Discrete probability distributions: general5.02b Expectation and variance: discrete random variables5.02c Linear coding: effects on mean and variance

  1. The discrete random variable \(X\) has probability generating function
$$\mathrm { G } _ { X } ( t ) = \frac { t ^ { 2 } } { ( 3 - 2 t ) ^ { 2 } }$$
  1. Specify the distribution of \(X\) A fair die is rolled repeatedly.
  2. Describe an outcome that could be modelled by the random variable \(X\)
  3. Use calculus and \(\mathrm { G } _ { X } ( t )\) to find
    1. \(\mathrm { E } ( X )\)
    2. \(\operatorname { Var } ( X )\) The discrete random variable \(Y\) has probability generating function $$\mathrm { G } _ { Y } ( t ) = \frac { t ^ { 10 } } { \left( 3 - 2 t ^ { 3 } \right) ^ { 2 } }$$
  4. Find the exact value of \(\mathrm { P } ( Y = 19 )\)

AnswerMarks Guidance
(a) NegBin\((r, p)\) has pgf \(\left[\frac{pt}{1-(1-p)t}\right]^r\) and identify the connection \(\mathbf{\text{NegBin}(2, \frac{1}{3})}\)M1, A1 2.1, 2.2a
(b) e.g. no. of rolls to achieve 5 or 6 (so that \(p = \frac{1}{3}\)) twice (oe)B1 ft 3.3
(c)(i) \(G_X'(t) = \frac{2t(3-2t)^2 - (-2) \times 2(3-2t)t^2}{(3-2t)^3}\) or \(\frac{6t}{(3-2t)^3}\)M1, A1 2.1, 1.1b
\(E(Y) = G_X'(1) = \mathbf{6}\)A1 1.1b
(ii) \(G_X''(t) = \frac{6(3-2t)^3 - (-2) \times 3(3-2t)^2 \times 6t}{(3-2t)^6}\) or \(\frac{18 + 24t}{(3-2t)^4}\)M1 2.1
\(G_X''(1) = \mathbf{42}\)A1 1.1b
Var\((X) = ''42'' + ''6'' - ''6''^2 = \mathbf{12}\)M1, A1 1.1b, 1.1b
(d) \(G_Y(t) = t^{10} \times \frac{1}{9}\left[1 - \frac{2}{3}t^3\right]^{-2} = \frac{1}{9}\left[1 + \ldots \frac{(-2)(-3)(-4)}{3!}\left(\frac{2}{3}\right)^3 t^9 \ldots\right]\)M1 A1 2.1, 1.1b
\(\text{P}(Y = 19) = \frac{32}{243}\)A1 1.1b
ALT Identify that \(Y = 3X + 4\)M1
\((Y = 19 \text{ requires } X = 5 \text{ so })\) \(\text{P}(X = 5) = \binom{4}{1}\left(\frac{1}{3}\right)\left(\frac{2}{3}\right)^3\left(\frac{1}{3}\right)\)A1
Notes:
(a) M1 for identifying the NegBin distribution (allow NB for NegBin)
A1 for \(r = 2\) and \(p = \frac{1}{3}\)
(b) B1 ft for identifying a suitable definition for \(X\) using a (fair) die, with \(p = \frac{1}{3}\) and the second occurrence of the event, only ft their NegBin distribution in (a). A finite number of rolls is B0
(c)(i) 1st M1 for attempt to differentiate quotient or product. At least one \(uv'\) style term correct. 1st A1 for a fully correct first derivative (needn't be simplified)
2nd A1 for E\((X) = 6\) NB this A1 depends on M1 only but M1A0A1 is possible
(ii) 2nd M1 for attempt to diff' quotient or product again. At least one \(uv'\) style term correct.
3rd A1 for 42 (may be given for incorrect G'' provided their G''\((1)\) gives 42 and M1 scored)
Note all powers of \((3 - 2t)\) equal 1 when \(t = 1\) is substituted so can be used as a check
3rd M1 for correct use of pgf to find Var\((X)\)
4th A1 dep on M3 for 12
(d) M1 for writing pgf in suitable form to carry out binomial expansion
1st A1 for a correct expression for coefficient of \(t^{19}\)
2nd A1 for \(\frac{32}{243}\) or exact equivalent
ALT M1 for identifying connection \(Y = 3X + 4\)
1st A1 for a correct numerical probability expression for P\((X = 5)\)
(Total: 13 marks)
**(a)** NegBin$(r, p)$ has pgf $\left[\frac{pt}{1-(1-p)t}\right]^r$ and identify the connection $\mathbf{\text{NegBin}(2, \frac{1}{3})}$ | M1, A1 | 2.1, 2.2a | (2)

**(b)** e.g. no. of rolls to achieve 5 or 6 (so that $p = \frac{1}{3}$) twice (oe) | B1 ft | 3.3 | (1)

**(c)(i)** $G_X'(t) = \frac{2t(3-2t)^2 - (-2) \times 2(3-2t)t^2}{(3-2t)^3}$ or $\frac{6t}{(3-2t)^3}$ | M1, A1 | 2.1, 1.1b |

$E(Y) = G_X'(1) = \mathbf{6}$ | A1 | 1.1b |

**(ii)** $G_X''(t) = \frac{6(3-2t)^3 - (-2) \times 3(3-2t)^2 \times 6t}{(3-2t)^6}$ or $\frac{18 + 24t}{(3-2t)^4}$ | M1 | 2.1 |

$G_X''(1) = \mathbf{42}$ | A1 | 1.1b |

Var$(X) = ''42'' + ''6'' - ''6''^2 = \mathbf{12}$ | M1, A1 | 1.1b, 1.1b | (7)

**(d)** $G_Y(t) = t^{10} \times \frac{1}{9}\left[1 - \frac{2}{3}t^3\right]^{-2} = \frac{1}{9}\left[1 + \ldots \frac{(-2)(-3)(-4)}{3!}\left(\frac{2}{3}\right)^3 t^9 \ldots\right]$ | M1 A1 | 2.1, 1.1b |

$\text{P}(Y = 19) = \frac{32}{243}$ | A1 | 1.1b | (3)

**ALT** Identify that $Y = 3X + 4$ | M1 |

$(Y = 19 \text{ requires } X = 5 \text{ so })$ $\text{P}(X = 5) = \binom{4}{1}\left(\frac{1}{3}\right)\left(\frac{2}{3}\right)^3\left(\frac{1}{3}\right)$ | A1 | | (13)

**Notes:**

(a) M1 for identifying the NegBin distribution (allow NB for NegBin)

A1 for $r = 2$ and $p = \frac{1}{3}$

(b) B1 ft for identifying a suitable definition for $X$ using a (fair) die, with $p = \frac{1}{3}$ and the second occurrence of the event, only ft their NegBin distribution in (a). A finite number of rolls is B0

(c)(i) 1st M1 for attempt to differentiate quotient or product. At least one $uv'$ style term correct. 1st A1 for a fully correct first derivative (needn't be simplified)

2nd A1 for E$(X) = 6$ NB this A1 depends on M1 only but M1A0A1 is possible

(ii) 2nd M1 for attempt to diff' quotient or product again. At least one $uv'$ style term correct.

3rd A1 for 42 (may be given for incorrect G'' provided their G''$(1)$ gives 42 and M1 scored)

Note all powers of $(3 - 2t)$ equal 1 when $t = 1$ is substituted so can be used as a check

3rd M1 for correct use of pgf to find Var$(X)$

4th A1 dep on M3 for 12

(d) M1 for writing pgf in suitable form to carry out binomial expansion

1st A1 for a correct expression for coefficient of $t^{19}$

2nd A1 for $\frac{32}{243}$ or exact equivalent

**ALT** M1 for identifying connection $Y = 3X + 4$

1st A1 for a correct numerical probability expression for P$(X = 5)$

**(Total: 13 marks)**

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\begin{enumerate}
  \item The discrete random variable $X$ has probability generating function
\end{enumerate}

$$\mathrm { G } _ { X } ( t ) = \frac { t ^ { 2 } } { ( 3 - 2 t ) ^ { 2 } }$$

(a) Specify the distribution of $X$

A fair die is rolled repeatedly.\\
(b) Describe an outcome that could be modelled by the random variable $X$\\
(c) Use calculus and $\mathrm { G } _ { X } ( t )$ to find\\
(i) $\mathrm { E } ( X )$\\
(ii) $\operatorname { Var } ( X )$

The discrete random variable $Y$ has probability generating function

$$\mathrm { G } _ { Y } ( t ) = \frac { t ^ { 10 } } { \left( 3 - 2 t ^ { 3 } \right) ^ { 2 } }$$

(d) Find the exact value of $\mathrm { P } ( Y = 19 )$

\hfill \mbox{\textit{Edexcel FS1 2023 Q6 [13]}}