CAIE P3 2023 November — Question 1 5 marks

Exam BoardCAIE
ModuleP3 (Pure Mathematics 3)
Year2023
SessionNovember
Marks5
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicModulus function
TypeSketch y=|linear| and y=linear, solve inequality: numeric coefficients
DifficultyModerate -0.8 Part (a) is a routine sketch of a single modulus function requiring identification of the vertex at x=0.5 and reflection of negative values. Part (b) involves solving a linear-modulus inequality by considering two cases, which is a standard technique. Both parts are straightforward applications of basic modulus concepts with minimal problem-solving required.
Spec1.02g Inequalities: linear and quadratic in single variable1.02s Modulus graphs: sketch graph of |ax+b|

1
  1. Sketch the graph of \(y = | 4 x - 2 |\).
  2. Solve the inequality \(1 + 3 x < | 4 x - 2 |\).

Question 1:
Part (a):
AnswerMarks Guidance
AnswerMarks Guidance
Sketch of \(y = \4x - 2\ \) — V-shaped graph, roughly symmetrical, extending into second quadrant, with vertex at \(\left(\frac{1}{2}, 0\right)\) and passing through \((0, 2)\); scale indicated on both axes; graph must extend beyond \((0, 2)\) and \((1, 2)\)
Total: 1
Question 1(b):
AnswerMarks Guidance
AnswerMark Guidance
Obtain critical value \(x = 3\)B1 Allow incorrect inequality. Allow if later rejected. Allow \(\frac{21}{7}\)
Solve the linear equation \(1 + 3x = 2 - 4x\)M1 Or corresponding linear inequality
Obtain critical value \(\frac{1}{7}\)A1 Allow 0.143 or better. Allow incorrect inequality. Allow if later rejected
Obtain final answer \(x < \frac{1}{7}\) [or] \(x > 3\)A1 Or equivalent. Allow with a comma, or nothing between. Strict inequalities only. Exact values. A0 for \(\frac{1}{7} > x > 3\). A0 for \(x < \frac{1}{7}\) and \(x > 3\)
Alternative method:
AnswerMarks Guidance
AnswerMark Guidance
Solve the quadratic inequality \((4x-2)^2 > (1+3x)^2\), or corresponding quadratic equationM1 e.g. \(7x^2 - 22x + 3 = 0\). Available if they start with correct equation/inequality, have correct method for squaring (i.e. not \((a+b)^2 = a^2 + b^2\)) and a correct method for solving. Need to obtain at least one critical value
Obtain critical value \(x = 3\)A1 Allow incorrect inequality. Allow if later rejected. Allow \(\frac{21}{7}\)
Obtain critical value \(\frac{1}{7}\)A1 Allow 0.143 or better. Allow incorrect inequality. Allow if later rejected
Obtain final answer \(x < \frac{1}{7}\) [or] \(x > 3\)A1 Or equivalent. Strict inequalities only. Allow with a comma, or nothing between. Exact values. A0 for \(\frac{1}{7} > x > 3\). A0 for \(x < \frac{1}{7}\) and \(x > 3\)
## Question 1:

**Part (a):**

| Answer | Marks | Guidance |
|--------|-------|----------|
| Sketch of $y = \|4x - 2\|$ — V-shaped graph, roughly symmetrical, extending into second quadrant, with vertex at $\left(\frac{1}{2}, 0\right)$ and passing through $(0, 2)$; scale indicated on both axes; graph must extend beyond $(0, 2)$ and $(1, 2)$ | B1 | Show a recognisable sketch of $y = \|4x-2\|$. Roughly symmetrical. Should extend into the second quadrant. Ignore $y = 4x-2$ below the axis if intention is clear e.g. dashed or the required lines are clearly bolder. Some indication of scale on **both** axes — accept dashes. Must go beyond $(0, 2)$ and $(1, 2)$. Ignore any attempt to sketch $y = 1 + 3x$. |
| | **Total: 1** | |

## Question 1(b):

| Answer | Mark | Guidance |
|--------|------|----------|
| Obtain critical value $x = 3$ | B1 | Allow incorrect inequality. Allow if later rejected. Allow $\frac{21}{7}$ |
| Solve the linear equation $1 + 3x = 2 - 4x$ | M1 | Or corresponding linear inequality |
| Obtain critical value $\frac{1}{7}$ | A1 | Allow 0.143 or better. Allow incorrect inequality. Allow if later rejected |
| Obtain final answer $x < \frac{1}{7}$ [or] $x > 3$ | A1 | Or equivalent. Allow with a comma, or nothing between. Strict inequalities only. Exact values. A0 for $\frac{1}{7} > x > 3$. A0 for $x < \frac{1}{7}$ **and** $x > 3$ |

**Alternative method:**

| Answer | Mark | Guidance |
|--------|------|----------|
| Solve the quadratic inequality $(4x-2)^2 > (1+3x)^2$, or corresponding quadratic equation | M1 | e.g. $7x^2 - 22x + 3 = 0$. Available if they start with correct equation/inequality, have correct method for squaring (i.e. not $(a+b)^2 = a^2 + b^2$) and a correct method for solving. Need to obtain at least one critical value |
| Obtain critical value $x = 3$ | A1 | Allow incorrect inequality. Allow if later rejected. Allow $\frac{21}{7}$ |
| Obtain critical value $\frac{1}{7}$ | A1 | Allow 0.143 or better. Allow incorrect inequality. Allow if later rejected |
| Obtain final answer $x < \frac{1}{7}$ [or] $x > 3$ | A1 | Or equivalent. Strict inequalities only. Allow with a comma, or nothing between. Exact values. A0 for $\frac{1}{7} > x > 3$. A0 for $x < \frac{1}{7}$ and $x > 3$ |

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1
\begin{enumerate}[label=(\alph*)]
\item Sketch the graph of $y = | 4 x - 2 |$.
\item Solve the inequality $1 + 3 x < | 4 x - 2 |$.
\end{enumerate}

\hfill \mbox{\textit{CAIE P3 2023 Q1 [5]}}