6 The parametric equations of a curve are
$$x = \sqrt { t } + 3 , \quad y = \ln t$$
for \(t > 0\).
- Obtain a simplified expression for \(\frac { \mathrm { d } y } { \mathrm {~d} x }\) in terms of \(t\).
- Hence find the exact coordinates of the point on the curve at which the gradient of the normal is - 2 .