| Exam Board | Edexcel |
|---|---|
| Module | CP AS (Core Pure AS) |
| Year | 2018 |
| Session | June |
| Marks | 11 |
| Paper | Download PDF ↗ |
| Mark scheme | Download PDF ↗ |
| Topic | Volumes of Revolution |
| Type | Applied context: real-world solid |
| Difficulty | Standard +0.3 This is a straightforward volumes of revolution question with a real-world context. Part (a) requires solving simultaneous equations from boundary conditions (routine algebra), part (b) is a standard π∫y² dx integration, part (c) asks for a model limitation (accessible discussion), and part (d) requires percentage comparison. All techniques are standard Core Pure AS level with no novel insights required, making it slightly easier than average. |
| Spec | 1.02m Graphs of functions: difference between plotting and sketching4.08d Volumes of revolution: about x and y axes |
| Answer | Marks | Guidance |
|---|---|---|
| Answer/Working | Mark | Guidance |
| \((4,14),(1,18)\Rightarrow 14=a(4)^2+b,\ 18=a(1)^2+b \Rightarrow a=\ldots, b=\ldots\) | M1 | |
| \(a=-\dfrac{4}{15},\ b=\dfrac{274}{15}\) | A1 |
| Answer | Marks | Guidance |
|---|---|---|
| Answer/Working | Mark | Guidance |
| \(\pi\times4^2\times14\) and \(\pi\times1^2\times10\) | B1 | |
| \(\pi\int x^2\,dy=\dfrac{\pi}{4}\int(274-15y)\,dy\) | B1ft | |
| \(=\dfrac{\pi}{4}\displaystyle\int_{14}^{18}(274-15y)\,dy\) | M1 | |
| \(=\dfrac{\pi}{4}\left[274y-\dfrac{15y^2}{2}\right]_{14}^{18}\) | M1, A1 | |
| \(V=234\pi+\dfrac{\pi}{4}\left[274(18)-\dfrac{15(18)^2}{2}-\left(274(14)-\dfrac{15(14)^2}{2}\right)\right]\) | ddM1 | |
| \(V=268\pi\approx842\text{ cm}^3\) | A1 |
| Answer | Marks | Guidance |
|---|---|---|
| Answer/Working | Mark | Guidance |
| Any one of: measurements may not be accurate; equation of curve may not be suitable model; bottom of bottle may not be flat; thickness of glass not considered; glass may not be smooth | B1 | Must refer to limitation of the model, e.g. measuring of dimensions, model used for curve, simplified model (thickness of glass, shape, smoothness) |
| Answer | Marks | Guidance |
|---|---|---|
| Answer/Working | Mark | Guidance |
| Comparison of their value to 750 (e.g. \(810-750=\ldots\)) AND conclusion consistent with their value (e.g. not a good model / this is a good model) | B1ft | Must demonstrate comparison, not just state percentage error or difference with no calculation. If answer \(<750\) conclude not good model; if \(>750\) give sensible consistent comment |
| Answer | Marks | Guidance |
|---|---|---|
| Answer/Working | Mark | Guidance |
| Substitutes \((4, 14)\) and \((1, 18)\) into the curve equation to obtain at least one correct equation | M1 | Attempts to find values of \(a\) and \(b\) |
| Correct values of \(a\) and \(b\) inferred from the data in the model | A1 |
| Answer | Marks | Guidance |
|---|---|---|
| Answer/Working | Mark | Guidance |
| Correct expressions for the 2 cylindrical parts | B1 | May be seen as a sum or as separate cylinders |
| Uses the model to obtain \(\pi\int\left(\dfrac{y - b}{a}\right)dy\) | B1ft | Note that the \(\pi\) may be recovered later |
| Chooses limits appropriate to the model: \(14\) and \(18\) | M1 | |
| Integrates to obtain an expression of the form \(\alpha y + \beta y^2\) | M1 | |
| Uses their model correctly to give \(274y - \dfrac{15y^2}{2}\) | A1 | |
| Uses the model to find the sum of their cylinders + their integrated volume | ddM1 | Must be fully correct method; dependent on both previous M marks; must have attempted volumes of cylinders "AHBG" and "CFED" and adds these to the magnitude of their integrated volume |
| \(268\pi\) or awrt \(842\) | A1 |
| Answer | Marks | Guidance |
|---|---|---|
| Answer/Working | Mark | Guidance |
| States an acceptable limitation of the model with no contradictory statements | B1 | Independent of part (b) |
| Answer | Marks | Guidance |
|---|---|---|
| Answer/Working | Mark | Guidance |
| Compares the actual volume to their answer to part (b) and makes an assessment of the model with a reason | B1ft | No contradictory statements |
## Question 9(a):
| Answer/Working | Mark | Guidance |
|---|---|---|
| $(4,14),(1,18)\Rightarrow 14=a(4)^2+b,\ 18=a(1)^2+b \Rightarrow a=\ldots, b=\ldots$ | M1 | |
| $a=-\dfrac{4}{15},\ b=\dfrac{274}{15}$ | A1 | |
---
## Question 9(b):
| Answer/Working | Mark | Guidance |
|---|---|---|
| $\pi\times4^2\times14$ and $\pi\times1^2\times10$ | B1 | |
| $\pi\int x^2\,dy=\dfrac{\pi}{4}\int(274-15y)\,dy$ | B1ft | |
| $=\dfrac{\pi}{4}\displaystyle\int_{14}^{18}(274-15y)\,dy$ | M1 | |
| $=\dfrac{\pi}{4}\left[274y-\dfrac{15y^2}{2}\right]_{14}^{18}$ | M1, A1 | |
| $V=234\pi+\dfrac{\pi}{4}\left[274(18)-\dfrac{15(18)^2}{2}-\left(274(14)-\dfrac{15(14)^2}{2}\right)\right]$ | ddM1 | |
| $V=268\pi\approx842\text{ cm}^3$ | A1 | |
---
## Question 9(c):
| Answer/Working | Mark | Guidance |
|---|---|---|
| Any one of: measurements may not be accurate; equation of curve may not be suitable model; bottom of bottle may not be flat; thickness of glass not considered; glass may not be smooth | B1 | Must refer to limitation of the model, e.g. measuring of dimensions, model used for curve, simplified model (thickness of glass, shape, smoothness) |
---
## Question 9(d):
| Answer/Working | Mark | Guidance |
|---|---|---|
| Comparison of their value to 750 (e.g. $810-750=\ldots$) AND conclusion consistent with their value (e.g. not a good model / this is a good model) | B1ft | Must demonstrate comparison, not just state percentage error or difference with no calculation. If answer $<750$ conclude not good model; if $>750$ give sensible consistent comment |
# Question (from mark scheme notes):
## Part (a):
| Answer/Working | Mark | Guidance |
|---|---|---|
| Substitutes $(4, 14)$ and $(1, 18)$ into the curve equation to obtain at least one correct equation | M1 | Attempts to find values of $a$ and $b$ |
| Correct values of $a$ and $b$ inferred from the data in the model | A1 | |
## Part (b):
| Answer/Working | Mark | Guidance |
|---|---|---|
| Correct expressions for the 2 cylindrical parts | B1 | May be seen as a sum or as separate cylinders |
| Uses the model to obtain $\pi\int\left(\dfrac{y - b}{a}\right)dy$ | B1ft | Note that the $\pi$ may be recovered later |
| Chooses limits appropriate to the model: $14$ and $18$ | M1 | |
| Integrates to obtain an expression of the form $\alpha y + \beta y^2$ | M1 | |
| Uses their model correctly to give $274y - \dfrac{15y^2}{2}$ | A1 | |
| Uses the model to find the sum of their cylinders + their integrated volume | ddM1 | Must be fully correct method; dependent on both previous M marks; must have attempted volumes of cylinders "AHBG" and "CFED" and adds these to the magnitude of their integrated volume |
| $268\pi$ or awrt $842$ | A1 | |
## Part (c):
| Answer/Working | Mark | Guidance |
|---|---|---|
| States an acceptable limitation of the model with no contradictory statements | B1 | Independent of part (b) |
## Part (d):
| Answer/Working | Mark | Guidance |
|---|---|---|
| Compares the actual volume to their answer to part (b) and makes an assessment of the model with a reason | B1ft | No contradictory statements |
9.
\begin{figure}[h]
\begin{center}
\includegraphics[alt={},max width=\textwidth]{e48fac26-15a2-4a5e-9204-9d49db8a998a-32_789_452_331_497}
\captionsetup{labelformat=empty}
\caption{Figure 1}
\end{center}
\end{figure}
\begin{figure}[h]
\begin{center}
\includegraphics[alt={},max width=\textwidth]{e48fac26-15a2-4a5e-9204-9d49db8a998a-32_681_523_424_1248}
\captionsetup{labelformat=empty}
\caption{Figure 2}
\end{center}
\end{figure}
A mathematics student is modelling the profile of a glass bottle of water. Figure 1 shows a sketch of a central vertical cross-section $A B C D E F G H A$ of the bottle with the measurements taken by the student.
The horizontal cross-section between $C F$ and $D E$ is a circle of diameter 8 cm and the horizontal cross-section between $B G$ and $A H$ is a circle of diameter 2 cm .
The student thinks that the curve $G F$ could be modelled as a curve with equation
$$y = a x ^ { 2 } + b \quad 1 \leqslant x \leqslant 4$$
where $a$ and $b$ are constants and $O$ is the fixed origin, as shown in Figure 2.
\begin{enumerate}[label=(\alph*)]
\item Find the value of $a$ and the value of $b$ according to the model.
\item Use the model to find the volume of water that the bottle can contain.
\item State a limitation of the model.
The label on the bottle states that the bottle holds approximately $750 \mathrm {~cm} ^ { 3 }$ of water.
\item Use this information and your answer to part (b) to evaluate the model, explaining your reasoning.
\end{enumerate}
\hfill \mbox{\textit{Edexcel CP AS 2018 Q9 [11]}}