WJEC Further Unit 5 2023 June — Question 1 11 marks

Exam BoardWJEC
ModuleFurther Unit 5 (Further Unit 5)
Year2023
SessionJune
Marks11
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicT-tests (unknown variance)
TypeUnbiased estimates calculation
DifficultyStandard +0.3 This is a straightforward one-sample t-test with clear hypotheses and small sample size. Part (a) requires standard calculations of sample mean and unbiased variance (dividing by n-1), part (b) is a routine one-tailed t-test at 5% level, and part (c) asks for a practical consideration. The question is slightly above average difficulty only because it's Further Maths content and requires knowledge of the t-distribution, but the execution is mechanical with no conceptual challenges or novel problem-solving required.
Spec5.05b Unbiased estimates: of population mean and variance5.05c Hypothesis test: normal distribution for population mean

  1. The average time it takes for a new kettle to boil, when full of water, is 305 seconds. An old kettle will take longer, on average, to boil. Alun suspects that a particular kettle is an old kettle. He boils the full kettle on 9 occasions and the times taken, in seconds, are shown below.
    305
    295
    310
    310
    315
    307
    300
    311
    306
You may assume the times taken to boil the full kettle are normally distributed.
  1. Calculate unbiased estimates for the mean and variance of the times taken to boil the full kettle.
  2. Test, at the \(5 \%\) level of significance, whether there is evidence to suggest that this is an old kettle.
  3. State a factor that Alun should control when carrying out this investigation.

AnswerMarks Guidance
(a)\(\sum x = 2759\), \(\sum x^2 = 846081\) B1
\(\bar{\mu} = 306.555...\)M1A1 M1 for appropriate use of calculator or use of \(\bar{\sigma}^2 = \frac{1}{n-1}(\sum x^2 - n\bar{x}^2)\). Allow 33.7122 from rounding \(\bar{\mu}\) to 306.56. M1A0 for 40.6096... from \(\bar{x} = 306.55\). M1A0 for 6.12 from \(\bar{x} = 306.6\). FT their \(\bar{\mu}\) for M1 only, provided \(\bar{\sigma}^2 > 0\)
\(\hat{\sigma}^2 = \frac{1}{8}(846081 - 9 \times 306.555...^2) = \frac{331}{9} = 36.777...\)
(b)\(H_0: \mu = 305\) and \(H_1: \mu > 305\) B1
\(DF = 8\)B1 si
\(CV = 1.860\)B1 FT their DF
\(t = \frac{306.5555...-305}{\sqrt{\frac{36.7777...}{9}}}\)M1 FT their \(\bar{\mu}\) and \(\hat{\sigma}^2\)
\(t = 0.7695...\)A1 cao. Accept 0.77 from correct working. Allow 0.806 from \(\bar{\mu} = 306.56\) and \(\hat{\sigma}^2 = 33.71(22)\)
Since \(0.7695 < 1.860\) there is insufficient evidence to reject \(H_0\).m1 FT their \(t\). Dep on use of t-distribution.
There is insufficient evidence to say that this is an old kettle.A1 cso
(c)Valid factor. e.g. the initial water temperature. e.g. the initial kettle temperature. e.g. the ambient temperature. e.g. the volume of water. e.g. the voltage going to the kettle. e.g. the mineral content of the water E1
Total [11]
(a) | $\sum x = 2759$, $\sum x^2 = 846081$ | B1 | At least 1dp |
| $\bar{\mu} = 306.555...$ | M1A1 | M1 for appropriate use of calculator or use of $\bar{\sigma}^2 = \frac{1}{n-1}(\sum x^2 - n\bar{x}^2)$. Allow 33.7122 from rounding $\bar{\mu}$ to 306.56. M1A0 for 40.6096... from $\bar{x} = 306.55$. M1A0 for 6.12 from $\bar{x} = 306.6$. FT their $\bar{\mu}$ for M1 only, provided $\bar{\sigma}^2 > 0$ |
| $\hat{\sigma}^2 = \frac{1}{8}(846081 - 9 \times 306.555...^2) = \frac{331}{9} = 36.777...$ | |

(b) | $H_0: \mu = 305$ and $H_1: \mu > 305$ | B1 | |
| $DF = 8$ | B1 | si |
| $CV = 1.860$ | B1 | FT their DF |
| $t = \frac{306.5555...-305}{\sqrt{\frac{36.7777...}{9}}}$ | M1 | FT their $\bar{\mu}$ and $\hat{\sigma}^2$ |
| $t = 0.7695...$ | A1 | cao. Accept 0.77 from correct working. Allow 0.806 from $\bar{\mu} = 306.56$ and $\hat{\sigma}^2 = 33.71(22)$ |
| Since $0.7695 < 1.860$ there is insufficient evidence to reject $H_0$. | m1 | FT their $t$. Dep on use of t-distribution. |
| There is insufficient evidence to say that this is an old kettle. | A1 | cso |

(c) | Valid factor. e.g. the initial water temperature. e.g. the initial kettle temperature. e.g. the ambient temperature. e.g. the volume of water. e.g. the voltage going to the kettle. e.g. the mineral content of the water | E1 | |

| **Total [11]** | | |

---
\begin{enumerate}
  \item The average time it takes for a new kettle to boil, when full of water, is 305 seconds. An old kettle will take longer, on average, to boil. Alun suspects that a particular kettle is an old kettle. He boils the full kettle on 9 occasions and the times taken, in seconds, are shown below.\\
305\\
295\\
310\\
310\\
315\\
307\\
300\\
311\\
306
\end{enumerate}

You may assume the times taken to boil the full kettle are normally distributed.\\
(a) Calculate unbiased estimates for the mean and variance of the times taken to boil the full kettle.\\
(b) Test, at the $5 \%$ level of significance, whether there is evidence to suggest that this is an old kettle.\\
(c) State a factor that Alun should control when carrying out this investigation.\\

\hfill \mbox{\textit{WJEC Further Unit 5 2023 Q1 [11]}}