WJEC Further Unit 3 2024 June — Question 4 7 marks

Exam BoardWJEC
ModuleFurther Unit 3 (Further Unit 3)
Year2024
SessionJune
Marks7
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicCircular Motion 1
TypeConical pendulum – horizontal circle in free space (no surface)
DifficultyModerate -0.3 This is a standard conical pendulum problem requiring resolution of forces (tension components balancing weight and providing centripetal force) and use of given trigonometric information. While it involves multiple steps (finding radius, resolving vertically and horizontally, solving for speed), the approach is entirely routine for Further Maths mechanics with no novel insight required. Slightly easier than average A-level due to the straightforward setup and given tan θ value.
Spec6.05c Horizontal circles: conical pendulum, banked tracks

  1. The diagram below shows a particle \(P\), of mass 5 kg , attached to one end of a light inextensible string of length 3 m . The other end is fixed at a point \(A\). The particle \(P\) is moving in a horizonal circle with centre \(C\), where the point \(C\) is vertically below \(A\). The string is inclined at an angle \(\theta\) to the downward vertical, where \(\tan \theta = \frac { 20 } { 21 }\). \includegraphics[max width=\textwidth, alt={}, center]{ae23a093-1419-4be4-8285-951650dc5a35-10_725_796_639_628}
Find the speed of the particle.

\begin{enumerate}
  \item The diagram below shows a particle $P$, of mass 5 kg , attached to one end of a light inextensible string of length 3 m . The other end is fixed at a point $A$. The particle $P$ is moving in a horizonal circle with centre $C$, where the point $C$ is vertically below $A$. The string is inclined at an angle $\theta$ to the downward vertical, where $\tan \theta = \frac { 20 } { 21 }$.\\
\includegraphics[max width=\textwidth, alt={}, center]{ae23a093-1419-4be4-8285-951650dc5a35-10_725_796_639_628}
\end{enumerate}

Find the speed of the particle.\\

\hfill \mbox{\textit{WJEC Further Unit 3 2024 Q4 [7]}}