| Exam Board | OCR MEI |
|---|---|
| Module | Further Mechanics Minor (Further Mechanics Minor) |
| Year | 2019 |
| Session | June |
| Marks | 8 |
| Paper | Download PDF ↗ |
| Mark scheme | Download PDF ↗ |
| Topic | Dimensional Analysis |
| Type | Find exponents with all unknowns |
| Difficulty | Standard +0.3 This is a straightforward dimensional analysis question with standard steps: recall dimensions of pressure, unit conversion, equate dimensions to find exponents (with all unknowns given), and apply the formula. While it requires multiple parts and careful algebraic manipulation, it follows a well-practiced template with no novel insight required, making it slightly easier than average. |
| Spec | 6.01a Dimensions: M, L, T notation6.01b Units vs dimensions: relationship6.01c Dimensional analysis: error checking6.01d Unknown indices: using dimensions |
| Answer | Marks | Guidance |
|---|---|---|
| 2 | (a) | M Lโ1 Tโ2 |
| Answer | Marks | Guidance |
|---|---|---|
| (b) | 0.0015 | B1 |
| Answer | Marks | Guidance |
|---|---|---|
| (c) | LTโ1 = (๐)(MLโ1Tโ2)๐ฅ(MLโ3)๐ฆ(L3)๐ง | M1 |
| M1 | 1.1 | Compare coeffs of M, L and T |
| Answer | Marks | Guidance |
|---|---|---|
| 2 2 | A1ft | 1.1 |
| Show z = 0 | A1 | 1.1 |
| Answer | Marks |
|---|---|
| (d) | 1 |
| Answer | Marks | Guidance |
|---|---|---|
| 1.29 | M1ft | 3.4 |
| Answer | Marks | Guidance |
|---|---|---|
| 0.166 | = 386.165โฆ | |
| Speed = 948 (m sโ1) | A1ft | 1.1 |
Question 2:
2 | (a) | M Lโ1 Tโ2 | B1 | 1.2
[1]
(b) | 0.0015 | B1 | 1.1
[1]
(c) | LTโ1 = (๐)(MLโ1Tโ2)๐ฅ(MLโ3)๐ฆ(L3)๐ง | M1 | 3.3 | Set up | M: 0 = ๐ฅ +๐ฆ
M1 | 1.1 | Compare coeffs of M, L and T | L: 1 = โ๐ฅ โ3๐ฆ+3๐ง
1 1
๐ฅ = ๐ฆ = โ
2 2 | A1ft | 1.1 | T: โ1 = โ2๐ฅ
Show z = 0 | A1 | 1.1 | AG
[4]
(d) | 1
๐ = 340รทโ
1.29 | M1ft | 3.4 | 1.29
Or speed = 340รโ
0.166 | = 386.165โฆ
Speed = 948 (m sโ1) | A1ft | 1.1 | 947.8066
[2]
2
\begin{enumerate}[label=(\alph*)]
\item Write down the dimensions of pressure.
The SI unit of pressure is the pascal (Pa). 15 Pa is equivalent to $Q$ newtons per square centimetre.
\item Find the value of $Q$.
Simon thinks the speed, $v$, of sound in a gas is given by the formula\\
$v = k P ^ { x } d ^ { y } V ^ { z }$,\\
where $P$ is the pressure of the gas,\\
$d$ is the density of the gas,\\
$V$ is the volume of the gas,\\
$k$ is a dimensionless constant.
\item Use dimensional analysis to
\begin{itemize}
\item find the values of $x$ and $y$ and
\item show that $z = 0$.\\[0pt]
[4]\\
At normal atmospheric pressure the density of air at sea level is $1.29 \mathrm {~kg} \mathrm {~m} ^ { - 3 }$. Under the same conditions the density of helium is $0.166 \mathrm {~kg} \mathrm {~m} ^ { - 3 }$.
\item Given that the speed of sound in air under these conditions is $340 \mathrm {~m} \mathrm {~s} ^ { - 1 }$, use Simon's formula to find the speed of sound in helium under the same conditions.
\end{itemize}
\end{enumerate}
\hfill \mbox{\textit{OCR MEI Further Mechanics Minor 2019 Q2 [8]}}