15 In an oscillating system, a particle of mass \(m \mathrm {~kg}\) moves in a horizontal line. Its displacement from its equilibrium position O at time \(t\) seconds is \(x\) metres, its velocity is \(v \mathrm {~ms} ^ { - 1 }\), and it is acted on by a force \(2 m x\) newtons acting towards O as shown in the diagram.
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Initially, the particle is projected away from O with speed \(1 \mathrm {~ms} ^ { - 1 }\) from a point 2 m from O in the positive direction.
- Show that the motion is modelled by the differential equation \(\frac { d ^ { 2 } x } { d t ^ { 2 } } + 2 x = 0\).
- State the type of motion.
- Write down the period of the motion.
- Find \(x\) in terms of \(t\).
- Find the amplitude of the motion.
- The motion is now damped by a force \(2 m v\) newtons.
- Show that \(\frac { d ^ { 2 } x } { d t ^ { 2 } } + 2 \frac { d x } { d t } + 2 x = 0\).
- State, giving a reason, whether the system is under-damped, critically damped or over-damped.
- Determine the general solution of this differential equation.
- Finally, a variable force \(2 m \cos 2 t\) newtons is added, so that the motion is now modelled by the differential equation
\(\frac { d ^ { 2 } x } { d t ^ { 2 } } + 2 \frac { d x } { d t } + 2 x = 2 \cos 2 t\).
- Find \(x\) in terms of \(t\).
In the long term, the particle is seen to perform simple harmonic motion with a period of just over 3 seconds.
- Verify that this behaviour is consistent with the answer to part (c)(i).