## Question 2:

| Answer | Mark | Guidance |
|--------|------|----------|
| State or imply the form $A + \frac{B}{2x+3} + \frac{C}{x-4}$ | B1 | $\frac{Dx+E}{2x+3} + \frac{F}{x-4}$ and $\frac{P}{2x+3} + \frac{Qx+R}{x-4}$ are also valid |
| Use a correct method for finding a constant | M1 | SC: If score B0, they can score M1 A1 for one correct constant. B0 M1 A0 available if they substitute two values to form simultaneous equations but get an incorrect answer, or they substitute one value and make an arithmetic error |
| Obtain one of $A = 3$, $B = -2$ and $C = 4$ | A1 | SC: If the horizontal equation is correct apart from an incorrect value for $A$, the other A marks may be available |
| Obtain a second value | A1 | SC: If denominator factorised as $\left(x+\frac{3}{2}\right)(x-4)$ can score a maximum of **B0 M1 A1 A1 A0** for a split involving 3 terms |
| Obtain a third value | A1 | ISW. Statement of the final split is not required |

**Alternative Method for Question 2:**

| Answer | Mark | Guidance |
|--------|------|----------|
| Divide numerator by denominator | (M1) | |
| Obtain $3\left(+\frac{Px+Q}{2x^2-5x-12}\right)$ | (A1) | $\left(3 + \frac{6x+20}{(2x+3)(x-4)}\right)$ |
| State or imply the form $\frac{Px+Q}{2x^2-5x-12} = \frac{D}{2x+3} + \frac{E}{x-4}$ | (B1) | Must deal with the 3 separately or include it correctly on both sides in their split |
| Obtain one of $D = -2$ and $E = 4$ | (A1) | SC: If denominator factorised as $\left(x+\frac{3}{2}\right)(x-4)$, then can score a maximum of **B0 M1 A1 A1 A0** for a split involving three terms |
| Obtain a second value | (A1) | ISW. Statement of the final split is not required |

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