Edexcel M5 2013 June — Question 1 7 marks

Exam BoardEdexcel
ModuleM5 (Mechanics 5)
Year2013
SessionJune
Marks7
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicFirst order differential equations (integrating factor)
TypeStandard linear first order - vector form
DifficultyStandard +0.8 This is a vector differential equation requiring integrating factor method (standard technique) but with non-standard initial conditions involving dot and cross products that must be unpacked into component form. The mechanics context and vector manipulation elevate it above routine first-order DE questions, requiring careful interpretation and multi-step reasoning beyond textbook exercises.
Spec4.10b Model with differential equations: kinematics and other contexts

  1. Solve the differential equation
$$\frac { \mathrm { d } \mathbf { r } } { \mathrm {~d} t } - 2 \mathbf { r } = \mathbf { 0 }$$ given that when \(t = 0 , \mathbf { r } . \mathbf { j } = 0\) and \(\mathbf { r } \times \mathbf { j } = \mathbf { i } + \mathbf { k }\).

Solve the differential equation \(\frac{dr}{dt} - 2r = 0\) given that when \(t = 0\), \(r \cdot j = 0\) and \(r \times j = i + k\).
(7 marks)
Solve the differential equation $\frac{dr}{dt} - 2r = 0$ given that when $t = 0$, $r \cdot j = 0$ and $r \times j = i + k$.

(7 marks)

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\begin{enumerate}
  \item Solve the differential equation
\end{enumerate}

$$\frac { \mathrm { d } \mathbf { r } } { \mathrm {~d} t } - 2 \mathbf { r } = \mathbf { 0 }$$

given that when $t = 0 , \mathbf { r } . \mathbf { j } = 0$ and $\mathbf { r } \times \mathbf { j } = \mathbf { i } + \mathbf { k }$.\\

\hfill \mbox{\textit{Edexcel M5 2013 Q1 [7]}}