Edexcel M5 2005 June — Question 7

Exam BoardEdexcel
ModuleM5 (Mechanics 5)
Year2005
SessionJune
TopicCentre of Mass 2

7. A uniform lamina of mass \(m\) is in the shape of an equilateral triangle \(A B C\) of perpendicular height \(h\). The lamina is free to rotate in a vertical plane about a fixed smooth horizontal axis \(L\) through \(A\) and perpendicular to the lamina.
  1. Show, by integration, that the moment of inertia of the lamina about \(L\) is \(\frac { 5 m h ^ { 2 } } { 9 }\). The centre of mass of the lamina is \(G\). The lamina is in equilibrium, with \(G\) below \(A\), when it is given an angular speed \(\sqrt { \left( \frac { 6 g } { 5 h } \right) }\).
  2. Find the angle between \(A G\) and the downward vertical, when the lamina first comes to rest.
  3. Find the greatest magnitude of the angular acceleration during the motion.
    (Total 17 marks)