OCR MEI M4 2013 June — Question 4 24 marks

Exam BoardOCR MEI
ModuleM4 (Mechanics 4)
Year2013
SessionJune
Marks24
PaperDownload PDF ↗
TopicMoments of inertia
TypeProve MI by integration
DifficultyChallenging +1.8 This M4 question requires multiple advanced techniques: deriving moment of inertia by integration, applying energy conservation to rotational motion, finding angular acceleration, and analyzing an impulsive collision with a peg. While each individual part follows standard M4 methods, the multi-stage problem with 7 parts requiring sustained reasoning about rotational dynamics, plus the non-trivial impulse calculation at a point away from the axis, places this significantly above average difficulty.
Spec6.02e Calculate KE and PE: using formulae6.02g Hooke's law: T = k*x or T = lambda*x/l6.04a Centre of mass: gravitational effect6.04b Find centre of mass: using symmetry

4 A uniform lamina of mass \(m\) is in the shape of a sector of a circle of radius \(a\) and angle \(\frac { 1 } { 3 } \pi\). It can rotate freely in a vertical plane about a horizontal axis perpendicular to the lamina through its vertex O .
  1. Show by integration that the moment of inertia of the lamina about the axis is \(\frac { 1 } { 2 } m a ^ { 2 }\).
  2. State the distance of the centre of mass of the lamina from the axis. The lamina is released from rest when one of the straight edges is horizontal as shown in Fig. 4.1. After time \(t\), the line of symmetry of the lamina makes an angle \(\theta\) with the downward vertical. \begin{figure}[h]
    \includegraphics[alt={},max width=\textwidth]{bc637a95-b469-493b-8fd4-d3b12049878b-3_257_441_1475_322} \captionsetup{labelformat=empty} \caption{Fig. 4.1}
    \end{figure} \begin{figure}[h]
    \includegraphics[alt={},max width=\textwidth]{bc637a95-b469-493b-8fd4-d3b12049878b-3_380_732_1635_1014} \captionsetup{labelformat=empty} \caption{Fig. 4.2}
    \end{figure}
  3. Show that \(\dot { \theta } ^ { 2 } = \frac { 4 g } { \pi a } ( 2 \cos \theta + 1 )\).
  4. Find the greatest speed attained by any point on the lamina.
  5. Find an expression for \(\ddot { \theta }\) in terms of \(\theta , a\) and \(g\). The lamina strikes a fixed peg at A where \(\mathrm { AO } = \frac { 3 } { 4 } a\) and is horizontal, as shown in Fig. 4.2. The collision reverses the direction of motion of the lamina and halves its angular speed.
  6. Find the magnitude of the impulse that the peg gives to the lamina.
  7. Determine the maximum value of \(\theta\) in the subsequent motion.

4 A uniform lamina of mass $m$ is in the shape of a sector of a circle of radius $a$ and angle $\frac { 1 } { 3 } \pi$. It can rotate freely in a vertical plane about a horizontal axis perpendicular to the lamina through its vertex O .\\
(i) Show by integration that the moment of inertia of the lamina about the axis is $\frac { 1 } { 2 } m a ^ { 2 }$.\\
(ii) State the distance of the centre of mass of the lamina from the axis.

The lamina is released from rest when one of the straight edges is horizontal as shown in Fig. 4.1. After time $t$, the line of symmetry of the lamina makes an angle $\theta$ with the downward vertical.

\begin{figure}[h]
\begin{center}
  \includegraphics[alt={},max width=\textwidth]{bc637a95-b469-493b-8fd4-d3b12049878b-3_257_441_1475_322}
\captionsetup{labelformat=empty}
\caption{Fig. 4.1}
\end{center}
\end{figure}

\begin{figure}[h]
\begin{center}
  \includegraphics[alt={},max width=\textwidth]{bc637a95-b469-493b-8fd4-d3b12049878b-3_380_732_1635_1014}
\captionsetup{labelformat=empty}
\caption{Fig. 4.2}
\end{center}
\end{figure}

(iii) Show that $\dot { \theta } ^ { 2 } = \frac { 4 g } { \pi a } ( 2 \cos \theta + 1 )$.\\
(iv) Find the greatest speed attained by any point on the lamina.\\
(v) Find an expression for $\ddot { \theta }$ in terms of $\theta , a$ and $g$.

The lamina strikes a fixed peg at A where $\mathrm { AO } = \frac { 3 } { 4 } a$ and is horizontal, as shown in Fig. 4.2. The collision reverses the direction of motion of the lamina and halves its angular speed.\\
(vi) Find the magnitude of the impulse that the peg gives to the lamina.\\
(vii) Determine the maximum value of $\theta$ in the subsequent motion.

\hfill \mbox{\textit{OCR MEI M4 2013 Q4 [24]}}