Edexcel M4 2002 June — Question 1 9 marks

Exam BoardEdexcel
ModuleM4 (Mechanics 4)
Year2002
SessionJune
Marks9
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicOblique and successive collisions
TypeOblique collision, vector velocity form
DifficultyStandard +0.8 This M4 oblique collision question requires applying conservation of momentum in two perpendicular directions, Newton's experimental law along the line of centres, and resolving an unknown velocity at a given angle. While the techniques are standard for M4, the multi-step coordination of several principles with careful vector resolution makes it moderately challenging, placing it above average difficulty but within reach of well-prepared Further Maths students.
Spec6.03b Conservation of momentum: 1D two particles6.03c Momentum in 2D: vector form6.03d Conservation in 2D: vector momentum6.03k Newton's experimental law: direct impact6.03l Newton's law: oblique impacts

1. \begin{figure}[h]
\captionsetup{labelformat=empty} \caption{Figure 1} \includegraphics[alt={},max width=\textwidth]{c68c85a1-9d80-4ced-bfb6-c7b5347e9bb8-2_450_1417_391_339}
\end{figure} Two smooth uniform spheres \(A\) and \(B\), of equal radius, are moving on a smooth horizontal plane. Sphere \(A\) has mass 2 kg and sphere \(B\) has mass 3 kg . The spheres collide and at the instant of collision the line joining their centres is parallel to \(\mathbf { i }\). Before the collision \(A\) has velocity ( \(3 \mathbf { i } - \mathbf { j }\) ) \(\mathrm { m } \mathrm { s } ^ { - 1 }\) and after the collision it has velocity \(( - 2 \mathbf { i } - \mathbf { j } ) \mathrm { m } \mathrm { s } ^ { - 1 }\). Before the collision the velocity of \(B\) makes an angle \(\alpha\) with the line of centres, as shown in Fig. 1, where \(\tan \alpha = 2\). The coefficient of restitution between the spheres is \(\frac { 1 } { 2 }\). Find, in terms of \(\mathbf { i }\) and \(\mathbf { j }\), the velocity of \(B\) before the collision.
(9)

1.

\begin{figure}[h]
\begin{center}
\captionsetup{labelformat=empty}
\caption{Figure 1}
  \includegraphics[alt={},max width=\textwidth]{c68c85a1-9d80-4ced-bfb6-c7b5347e9bb8-2_450_1417_391_339}
\end{center}
\end{figure}

Two smooth uniform spheres $A$ and $B$, of equal radius, are moving on a smooth horizontal plane. Sphere $A$ has mass 2 kg and sphere $B$ has mass 3 kg . The spheres collide and at the instant of collision the line joining their centres is parallel to $\mathbf { i }$. Before the collision $A$ has velocity ( $3 \mathbf { i } - \mathbf { j }$ ) $\mathrm { m } \mathrm { s } ^ { - 1 }$ and after the collision it has velocity $( - 2 \mathbf { i } - \mathbf { j } ) \mathrm { m } \mathrm { s } ^ { - 1 }$. Before the collision the velocity of $B$ makes an angle $\alpha$ with the line of centres, as shown in Fig. 1, where $\tan \alpha = 2$. The coefficient of restitution between the spheres is $\frac { 1 } { 2 }$.

Find, in terms of $\mathbf { i }$ and $\mathbf { j }$, the velocity of $B$ before the collision.\\
(9)\\

\hfill \mbox{\textit{Edexcel M4 2002 Q1 [9]}}