Edexcel M3 — Question 3 10 marks

Exam BoardEdexcel
ModuleM3 (Mechanics 3)
Marks10
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicSimple Harmonic Motion
TypeTime to travel between positions
DifficultyStandard +0.3 This is a standard SHM question requiring knowledge of amplitude-period relationships and position-time equations. Part (a) is routine (v_max = ωa). Part (b) involves solving x = a cos(ωt) for two positions and finding the time difference, which is a common textbook exercise requiring careful setup but no novel insight. The 6 marks reflect moderate working rather than conceptual difficulty.
Spec4.10f Simple harmonic motion: x'' = -omega^2 x

3. A particle is performing simple harmonic motion along a straight line between the points \(A\) and \(B\) where \(A B = 8 \mathrm {~m}\). The period of the motion is 12 seconds.
  1. Find the maximum speed of the particle in terms of \(\pi\). The points \(P\) and \(Q\) are on the line \(A B\) at distances of 3 m and 6 m respectively from \(A\).
  2. Find, correct to 3 significant figures, the time it takes for the particle to travel directly from \(P\) to \(Q\).
    (6 marks)

AnswerMarks Guidance
(a) amplitude \(= \frac{1}{2} \times 8 = 4\) mB1
period \(= \frac{2\pi}{\omega} = 12 \therefore \omega = \frac{\pi}{6}\)B1
\(v_{\max} = a\omega = 4 \times \frac{\pi}{6} = \frac{2\pi}{3}\) ms\(^{-1}\)M1 A1
(b) \(x = a \sin \omega t\)M1
at P, \(1 = 4 \sin \omega t \therefore \frac{\pi}{6}t = 0.2527, t = 0.4826\)M1 A1
at Q, \(2 = 4 \sin \omega t \therefore \frac{\pi}{6}t = \frac{\pi}{6}, t = 1\)M1 A1
\(\therefore\) time between \(= 1.48\) s (3sf)A1 (10)
(a) amplitude $= \frac{1}{2} \times 8 = 4$ m | B1

period $= \frac{2\pi}{\omega} = 12 \therefore \omega = \frac{\pi}{6}$ | B1

$v_{\max} = a\omega = 4 \times \frac{\pi}{6} = \frac{2\pi}{3}$ ms$^{-1}$ | M1 A1

(b) $x = a \sin \omega t$ | M1

at P, $1 = 4 \sin \omega t \therefore \frac{\pi}{6}t = 0.2527, t = 0.4826$ | M1 A1

at Q, $2 = 4 \sin \omega t \therefore \frac{\pi}{6}t = \frac{\pi}{6}, t = 1$ | M1 A1

$\therefore$ time between $= 1.48$ s (3sf) | A1 | (10)

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3. A particle is performing simple harmonic motion along a straight line between the points $A$ and $B$ where $A B = 8 \mathrm {~m}$. The period of the motion is 12 seconds.
\begin{enumerate}[label=(\alph*)]
\item Find the maximum speed of the particle in terms of $\pi$.

The points $P$ and $Q$ are on the line $A B$ at distances of 3 m and 6 m respectively from $A$.
\item Find, correct to 3 significant figures, the time it takes for the particle to travel directly from $P$ to $Q$.\\
(6 marks)
\end{enumerate}

\hfill \mbox{\textit{Edexcel M3  Q3 [10]}}