OCR M3 Specimen — Question 3 8 marks

Exam BoardOCR
ModuleM3 (Mechanics 3)
SessionSpecimen
Marks8
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicVariable Force
TypeAir resistance kv² - horizontal motion or engine power
DifficultyStandard +0.8 This is a standard M3 variable force problem requiring the v dv/dx = a technique and integration with a quadratic resistance term. While the setup is routine for M3 students, the algebraic manipulation and integration of 1/(constant + v²) requires careful execution and knowledge of arctan integration, placing it moderately above average difficulty.
Spec3.02f Non-uniform acceleration: using differentiation and integration3.02g Two-dimensional variable acceleration6.06a Variable force: dv/dt or v*dv/dx methods

3 An aircraft of mass 80000 kg travelling at \(90 \mathrm {~m} \mathrm {~s} ^ { - 1 }\) touches down on a straight horizontal runway. It is brought to rest by braking and resistive forces which together are modelled by a horizontal force of magnitude ( \(27000 + 50 v ^ { 2 }\) ) newtons, where \(v \mathrm {~m} \mathrm {~s} ^ { - 1 }\) is the speed of the aircraft. Find the distance travelled by the aircraft between touching down and coming to rest.

Question 3 (first):
AnswerMarks Guidance
Answer/WorkingMarks Guidance
(i) \(A\) and \(B\) move off \(\perp\) and \(\\) resp. to line of centres M1
\(2mv_B = mu\cos\theta\)A1 For correct momentum equation
\(v_B = eu\cos\theta\)A1 For correct restitution equation
Hence \(e = 0.5\)A1 [4] For correct answer \(0.5\)
(ii) \(v_A = u\sin\theta\)B1 For correct equation
Hence \(v_A = v_B \Rightarrow u\sin\theta = 0.5u\cos\theta\)M1 For forming the relevant equation for \(\theta\)
So \(\theta = \tan^{-1}0.5 \approx 26.6°\)A1 [3] For correct value \(26.6\)
Question 3 (second):
AnswerMarks Guidance
Answer/WorkingMarks Guidance
\(80000v\frac{dv}{dx} = -(27000 + 50v^2)\)M1 For using Newton II to form a DE
A1For correct equation including \(v\frac{dv}{dx}\)
Hence \(x = -\int\frac{1600v}{540+v^2}\,dv\)M1 For separation of variables
\(= -800\ln(540+v^2) + k\)M1 For logarithmic form of integral
A1\(\checkmark\)For correct integration of \(\frac{av}{b+cv^2}\)
\(v=90\) when \(x=0 \Rightarrow k = 800\ln 8640\)M1 For use of initial condition to find \(k\)
Hence when \(v=0\), \(x = 800\ln 16\)M1 For evaluation of required distance
So distance is \(2220\) m approximatelyA1 [8] For correct value \(2220\)
# Question 3 (first):

| Answer/Working | Marks | Guidance |
|---|---|---|
| **(i)** $A$ and $B$ move off $\perp$ and $\|$ resp. to line of centres | M1 | For correct directions of motion after impact |
| $2mv_B = mu\cos\theta$ | A1 | For correct momentum equation |
| $v_B = eu\cos\theta$ | A1 | For correct restitution equation |
| Hence $e = 0.5$ | A1 **[4]** | For correct answer $0.5$ |
| **(ii)** $v_A = u\sin\theta$ | B1 | For correct equation |
| Hence $v_A = v_B \Rightarrow u\sin\theta = 0.5u\cos\theta$ | M1 | For forming the relevant equation for $\theta$ |
| So $\theta = \tan^{-1}0.5 \approx 26.6°$ | A1 **[3]** | For correct value $26.6$ |

---

# Question 3 (second):

| Answer/Working | Marks | Guidance |
|---|---|---|
| $80000v\frac{dv}{dx} = -(27000 + 50v^2)$ | M1 | For using Newton II to form a DE |
| | A1 | For correct equation including $v\frac{dv}{dx}$ |
| Hence $x = -\int\frac{1600v}{540+v^2}\,dv$ | M1 | For separation of variables |
| $= -800\ln(540+v^2) + k$ | M1 | For logarithmic form of integral |
| | A1$\checkmark$ | For correct integration of $\frac{av}{b+cv^2}$ |
| $v=90$ when $x=0 \Rightarrow k = 800\ln 8640$ | M1 | For use of initial condition to find $k$ |
| Hence when $v=0$, $x = 800\ln 16$ | M1 | For evaluation of required distance |
| So distance is $2220$ m approximately | A1 **[8]** | For correct value $2220$ |

---
3 An aircraft of mass 80000 kg travelling at $90 \mathrm {~m} \mathrm {~s} ^ { - 1 }$ touches down on a straight horizontal runway. It is brought to rest by braking and resistive forces which together are modelled by a horizontal force of magnitude ( $27000 + 50 v ^ { 2 }$ ) newtons, where $v \mathrm {~m} \mathrm {~s} ^ { - 1 }$ is the speed of the aircraft. Find the distance travelled by the aircraft between touching down and coming to rest.

\hfill \mbox{\textit{OCR M3  Q3 [8]}}