OCR M3 2007 June — Question 1 6 marks

Exam BoardOCR
ModuleM3 (Mechanics 3)
Year2007
SessionJune
Marks6
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicSimple Harmonic Motion
TypeMaximum speed in SHM
DifficultyModerate -0.5 This is a straightforward application of standard SHM formulas (v_max = ωa and v² = ω²(a² - x²)) with given values. Requires recall of formulas and basic substitution/algebra, but no problem-solving insight or complex manipulation, making it slightly easier than average.
Spec4.10f Simple harmonic motion: x'' = -omega^2 x

1 A particle \(P\) is moving with simple harmonic motion in a straight line. The period is 6.1 s and the amplitude is 3 m . Calculate, in either order,
  1. the maximum speed of \(P\),
  2. the distance of \(P\) from the centre of motion when \(P\) has speed \(2.5 \mathrm {~ms} ^ { - 1 }\).

Question 1:
Part (i)
AnswerMarks Guidance
Answer/WorkingMark Guidance
\([\omega = 2\pi/6.1 = 1.03]\)M1 For using \(T = 2\pi/\omega\)
M1For using \(v_{max} = a\omega\)
Speed is \(3.09 \text{ ms}^{-1}\)A1 [3 marks total]
Part (ii)
AnswerMarks Guidance
Answer/WorkingMark Guidance
M1For using \(v^2 = \omega^2(A^2 - x^2)\) or for using \(v = A\omega\cos\omega t\) and \(x = A\sin\omega t\)
\(2.5^2 = 1.03^2(3^2 - x^2)\) or \(x = 3\sin(1.03 \times 0.60996...)\)A1ft ft incorrect \(\omega\)
Distance is 1.76mA1 [3 marks total]
# Question 1:

## Part (i)
| Answer/Working | Mark | Guidance |
|---|---|---|
| $[\omega = 2\pi/6.1 = 1.03]$ | M1 | For using $T = 2\pi/\omega$ |
| | M1 | For using $v_{max} = a\omega$ |
| Speed is $3.09 \text{ ms}^{-1}$ | A1 | [3 marks total] |

## Part (ii)
| Answer/Working | Mark | Guidance |
|---|---|---|
| | M1 | For using $v^2 = \omega^2(A^2 - x^2)$ or for using $v = A\omega\cos\omega t$ and $x = A\sin\omega t$ |
| $2.5^2 = 1.03^2(3^2 - x^2)$ or $x = 3\sin(1.03 \times 0.60996...)$ | A1ft | ft incorrect $\omega$ |
| Distance is 1.76m | A1 | [3 marks total] |

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1 A particle $P$ is moving with simple harmonic motion in a straight line. The period is 6.1 s and the amplitude is 3 m . Calculate, in either order,\\
(i) the maximum speed of $P$,\\
(ii) the distance of $P$ from the centre of motion when $P$ has speed $2.5 \mathrm {~ms} ^ { - 1 }$.

\hfill \mbox{\textit{OCR M3 2007 Q1 [6]}}