| Exam Board | AQA |
|---|---|
| Module | M3 (Mechanics 3) |
| Year | 2015 |
| Session | June |
| Marks | 4 |
| Paper | Download PDF ↗ |
| Mark scheme | Download PDF ↗ |
| Topic | Momentum and Collisions 1 |
| Type | Particle-wall perpendicular collision |
| Difficulty | Moderate -0.3 This is a straightforward two-part mechanics question requiring standard application of impulse-momentum theorem and coefficient of restitution formula. Part (a) uses Pythagoras to find the impulse from perpendicular velocity components, and part (b) applies e = speed of separation/speed of approach with simple vector resolution. Both are routine M3 techniques with no novel problem-solving required, making it slightly easier than average. |
| Spec | 1.10c Magnitude and direction: of vectors6.03e Impulse: by a force6.03f Impulse-momentum: relation6.03j Perfectly elastic/inelastic: collisions6.03k Newton's experimental law: direct impact6.03l Newton's law: oblique impacts |
I notice that the content you've provided only shows "Question 3: 3" without any actual mark scheme details to clean up.
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- Formatting with one marking point per line3 A disc of mass 0.5 kg is moving with speed $3 \mathrm {~m} \mathrm {~s} ^ { - 1 }$ on a smooth horizontal surface when it receives a horizontal impulse in a direction perpendicular to its direction of motion. Immediately after the impulse, the disc has speed $5 \mathrm {~m} \mathrm {~s} ^ { - 1 }$.
\begin{enumerate}[label=(\alph*)]
\item Find the magnitude of the impulse received by the disc.
\item Before the impulse, the disc is moving parallel to a smooth vertical wall, as shown in the diagram.
\section*{11/1/1/1/1/1/1/1/1/1/1/1/ Wall}
$$\overbrace { 3 \mathrm {~ms} ^ { - 1 } } ^ { \underset { < } { \bigcirc } } \text { Disc }$$
After the impulse, the disc hits the wall and rebounds with speed $3 \sqrt { 2 } \mathrm {~m} \mathrm {~s} ^ { - 1 }$.\\
Find the coefficient of restitution between the disc and the wall.\\[0pt]
[4 marks]
\end{enumerate}
\hfill \mbox{\textit{AQA M3 2015 Q3 [4]}}