AQA M3 2008 June — Question 4 10 marks

Exam BoardAQA
ModuleM3 (Mechanics 3)
Year2008
SessionJune
Marks10
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicOblique and successive collisions
TypeOblique collision, vector velocity form
DifficultyStandard +0.3 This is a standard M3 oblique collision question requiring conservation of momentum (straightforward vector arithmetic), angle calculation using dot product, impulse from momentum change, and recognizing that impulse direction equals line of centres. All techniques are routine for this topic with no novel insight required, making it slightly easier than average.
Spec1.10c Magnitude and direction: of vectors1.10d Vector operations: addition and scalar multiplication6.03b Conservation of momentum: 1D two particles6.03c Momentum in 2D: vector form6.03e Impulse: by a force6.03f Impulse-momentum: relation

4 Two smooth spheres, \(A\) and \(B\), have equal radii and masses \(m\) and \(2 m\) respectively. The spheres are moving on a smooth horizontal plane. The sphere \(A\) has velocity ( \(4 \mathbf { i } + 3 \mathbf { j }\) ) when it collides with the sphere \(B\) which has velocity \(( - 2 \mathbf { i } + 2 \mathbf { j } )\). After the collision, the velocity of \(B\) is \(( \mathbf { i } + \mathbf { j } )\).
  1. Find the velocity of \(A\) immediately after the collision.
  2. Find the angle between the velocities of \(A\) and \(B\) immediately after the collision.
  3. Find the impulse exerted by \(B\) on \(A\).
  4. State, as a vector, the direction of the line of centres of \(A\) and \(B\) when they collide.
    (1 mark)

Question 4:
Part (a):
AnswerMarks Guidance
Answer/WorkingMarks Guidance
CLM: \(m(4\mathbf{i}+3\mathbf{j})+2m(-2\mathbf{i}+2\mathbf{j}) = mv+2m(\mathbf{i}+\mathbf{j})\)M1
\(7\mathbf{j} = v+(2\mathbf{i}+2\mathbf{j})\)
\(v = -2\mathbf{i}+5\mathbf{j}\)A2,1,0 A1 for one slip. Total: 3
Part (b):
AnswerMarks Guidance
Answer/WorkingMarks Guidance
Angle with \(\mathbf{j}\) direction: \(A\): \(\tan^{-1}\frac{2}{5}=21.8°\) OE in \(\mathbf{i}\) direction
\(B\): \(\tan^{-1}\frac{1}{1}=45°\)M1 M1 for two inverse tan and addition of angles
The angle \(= 21.8°+45°=67°\)A1F AWRT
Alternative: \((-2\mathbf{i}+5\mathbf{j})\cdot(\mathbf{i}+\mathbf{j})=\sqrt{29}\times\sqrt{2}\cos\theta\)(M1) Not in specification
\(\cos\theta = \frac{3}{\sqrt{58}}\)(A1)
\(\theta = 67°\)(A1F) awrt. Total: 3
Part (c):
AnswerMarks Guidance
Answer/WorkingMarks Guidance
The impulse \(=\) Gain in momentum of \(A\)M1
\(= m(-2\mathbf{i}+5\mathbf{j})-m(4\mathbf{i}+3\mathbf{j})\)A1F
\(= -6m\mathbf{i}+2m\mathbf{j}\)A1F Total: 3
Part (d):
AnswerMarks Guidance
Answer/WorkingMarks Guidance
\(-3\mathbf{i}+\mathbf{j}\) or any scalar multiple of \(-3\mathbf{i}+\mathbf{j}\)B1 Total: 1
## Question 4:

### Part (a):
| Answer/Working | Marks | Guidance |
|---|---|---|
| CLM: $m(4\mathbf{i}+3\mathbf{j})+2m(-2\mathbf{i}+2\mathbf{j}) = mv+2m(\mathbf{i}+\mathbf{j})$ | M1 | |
| $7\mathbf{j} = v+(2\mathbf{i}+2\mathbf{j})$ | | |
| $v = -2\mathbf{i}+5\mathbf{j}$ | A2,1,0 | A1 for one slip. **Total: 3** |

### Part (b):
| Answer/Working | Marks | Guidance |
|---|---|---|
| Angle with $\mathbf{j}$ direction: $A$: $\tan^{-1}\frac{2}{5}=21.8°$ | | OE in $\mathbf{i}$ direction |
| $B$: $\tan^{-1}\frac{1}{1}=45°$ | M1 | M1 for two inverse tan and addition of angles |
| The angle $= 21.8°+45°=67°$ | A1F | AWRT |
| **Alternative:** $(-2\mathbf{i}+5\mathbf{j})\cdot(\mathbf{i}+\mathbf{j})=\sqrt{29}\times\sqrt{2}\cos\theta$ | (M1) | Not in specification |
| $\cos\theta = \frac{3}{\sqrt{58}}$ | (A1) | |
| $\theta = 67°$ | (A1F) | awrt. **Total: 3** |

### Part (c):
| Answer/Working | Marks | Guidance |
|---|---|---|
| The impulse $=$ Gain in momentum of $A$ | M1 | |
| $= m(-2\mathbf{i}+5\mathbf{j})-m(4\mathbf{i}+3\mathbf{j})$ | A1F | |
| $= -6m\mathbf{i}+2m\mathbf{j}$ | A1F | **Total: 3** |

### Part (d):
| Answer/Working | Marks | Guidance |
|---|---|---|
| $-3\mathbf{i}+\mathbf{j}$ or any scalar multiple of $-3\mathbf{i}+\mathbf{j}$ | B1 | **Total: 1** |

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4 Two smooth spheres, $A$ and $B$, have equal radii and masses $m$ and $2 m$ respectively. The spheres are moving on a smooth horizontal plane. The sphere $A$ has velocity ( $4 \mathbf { i } + 3 \mathbf { j }$ ) when it collides with the sphere $B$ which has velocity $( - 2 \mathbf { i } + 2 \mathbf { j } )$. After the collision, the velocity of $B$ is $( \mathbf { i } + \mathbf { j } )$.
\begin{enumerate}[label=(\alph*)]
\item Find the velocity of $A$ immediately after the collision.
\item Find the angle between the velocities of $A$ and $B$ immediately after the collision.
\item Find the impulse exerted by $B$ on $A$.
\item State, as a vector, the direction of the line of centres of $A$ and $B$ when they collide.\\
(1 mark)
\end{enumerate}

\hfill \mbox{\textit{AQA M3 2008 Q4 [10]}}