OCR MEI M2 2011 June — Question 3 18 marks

Exam BoardOCR MEI
ModuleM2 (Mechanics 2)
Year2011
SessionJune
Marks18
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicCentre of Mass 1
TypeFolded lamina
DifficultyStandard +0.3 This is a standard M2 centre of mass question with routine composite shapes and folding. Part (i) requires decomposing a 2D lamina into rectangles—straightforward calculation. Part (ii) is basic statics with two tensions. Parts (iii-iv) involve folding into 3D, which adds a step but follows a standard template. The 'show that' format guides students to the answer. Slightly easier than average due to its structured, methodical nature with no novel problem-solving required.
Spec3.03m Equilibrium: sum of resolved forces = 06.04b Find centre of mass: using symmetry6.04c Composite bodies: centre of mass

3 A bracket is being made from a sheet of uniform thin metal. Firstly, a plate is cut from a square of the sheet metal in the shape OABCDEFHJK, shown shaded in Fig. 3.1. The dimensions shown in the figure are in centimetres; axes \(\mathrm { O } x\) and \(\mathrm { O } y\) are also shown. \begin{figure}[h]
\includegraphics[alt={},max width=\textwidth]{1dd32b82-020e-45ef-8146-892197fd0985-4_561_569_429_788} \captionsetup{labelformat=empty} \caption{Fig. 3.1}
\end{figure}
  1. Show that, referred to the axes given in Fig. 3.1, the centre of mass of the plate OABCDEFHJK has coordinates (0.8, 2.5). The plate is hung using light vertical strings attached to \(\mathbf { J }\) and \(\mathbf { H }\). The edge \(\mathbf { J H }\) is horizontal and the plate is in equilibrium. The weight of the plate is 3.2 N .
  2. Calculate the tensions in each of the strings. The plate is now bent to form the bracket. This is shown in Fig. 3.2: the rectangle IJKO is folded along the line IA so that it is perpendicular to the plane ABCGHI ; the rectangle DEFG is folded along the line DG so it is also perpendicular to the plane ABCGHI but on the other side of it. Fig. 3.2 also shows the axes \(\mathrm { O } x , \mathrm { O } y\) and \(\mathrm { O } z\). \begin{figure}[h]
    \includegraphics[alt={},max width=\textwidth]{1dd32b82-020e-45ef-8146-892197fd0985-4_611_782_1713_678} \captionsetup{labelformat=empty} \caption{Fig. 3.2}
    \end{figure}
  3. Show that, referred to the axes given in Fig. 3.2, the centre of mass of the bracket has coordinates ( \(1,2.7,0\) ). The bracket is now hung freely in equilibrium from a string attached to O .
  4. Calculate the angle between the edge OI and the vertical.

Question 3:
Part (i)
AnswerMarks Guidance
Working/AnswerMarks Guidance
Split shape into rectangles, find areas and centroidsM1 Valid method
E.g. Large rectangle (main body) + pieces, correct areasA1 Correct areas stated
\(\bar{x} = \frac{\sum A_i x_i}{\sum A_i}\), correct calculation giving \(\bar{x} = 0.8\)A1
\(\bar{y} = \frac{\sum A_i y_i}{\sum A_i}\), correct calculation giving \(\bar{y} = 2.5\)A1
Part (ii)
AnswerMarks Guidance
Working/AnswerMarks Guidance
J is at \((-1, 4)\), H is at \((3, 4)\) in original coordsB1 Positions of J and H identified
\(\bar{x} = 0.8\) from J: distance \(= 0.8-(-1) = 1.8\) from J; distance from H \(= 3 - 0.8 = 2.2\)M1 Moments of tensions about a point
Taking moments: \(T_J \times 4 + T_H \times 0 = 3.2 \times 2.2\) or equivalentM1 Correct moment equation
\(T_J = \frac{3.2 \times 2.2}{4} = 1.76 \text{ N}\)A1
\(T_H = 3.2 - 1.76 = 1.44 \text{ N}\)A1
Part (iii)
AnswerMarks Guidance
Working/AnswerMarks Guidance
IJKO rectangle folds up: its centroid moves from original position to new 3D positionM1
DEFG rectangle folds down: centroid moves to new 3D positionM1
Correct \(x\)-coordinate \(= 1\) shownA1
Correct \(y\)-coordinate \(= 2.7\) shownA1
Correct \(z\)-coordinate \(= 0\) shownA1
Part (iv)
AnswerMarks Guidance
Working/AnswerMarks Guidance
O is at \((0,0,0)\), I is at \((0,1,0)\) in bracket axes; centre of mass at \((1, 2.7, 0)\)M1 Use coordinates to find angle
The string at O: bracket hangs so COM is directly below OM1
OI is along \(y\)-axis; angle between OI and vertical: \(\tan\theta = \frac{1}{2.7}\) or equivalentA1
\(\theta \approx 20.3°\)A1
# Question 3:

## Part (i)
| Working/Answer | Marks | Guidance |
|---|---|---|
| Split shape into rectangles, find areas and centroids | M1 | Valid method |
| E.g. Large rectangle (main body) + pieces, correct areas | A1 | Correct areas stated |
| $\bar{x} = \frac{\sum A_i x_i}{\sum A_i}$, correct calculation giving $\bar{x} = 0.8$ | A1 | |
| $\bar{y} = \frac{\sum A_i y_i}{\sum A_i}$, correct calculation giving $\bar{y} = 2.5$ | A1 | |

## Part (ii)
| Working/Answer | Marks | Guidance |
|---|---|---|
| J is at $(-1, 4)$, H is at $(3, 4)$ in original coords | B1 | Positions of J and H identified |
| $\bar{x} = 0.8$ from J: distance $= 0.8-(-1) = 1.8$ from J; distance from H $= 3 - 0.8 = 2.2$ | M1 | Moments of tensions about a point |
| Taking moments: $T_J \times 4 + T_H \times 0 = 3.2 \times 2.2$ or equivalent | M1 | Correct moment equation |
| $T_J = \frac{3.2 \times 2.2}{4} = 1.76 \text{ N}$ | A1 | |
| $T_H = 3.2 - 1.76 = 1.44 \text{ N}$ | A1 | |

## Part (iii)
| Working/Answer | Marks | Guidance |
|---|---|---|
| IJKO rectangle folds up: its centroid moves from original position to new 3D position | M1 | |
| DEFG rectangle folds down: centroid moves to new 3D position | M1 | |
| Correct $x$-coordinate $= 1$ shown | A1 | |
| Correct $y$-coordinate $= 2.7$ shown | A1 | |
| Correct $z$-coordinate $= 0$ shown | A1 | |

## Part (iv)
| Working/Answer | Marks | Guidance |
|---|---|---|
| O is at $(0,0,0)$, I is at $(0,1,0)$ in bracket axes; centre of mass at $(1, 2.7, 0)$ | M1 | Use coordinates to find angle |
| The string at O: bracket hangs so COM is directly below O | M1 | |
| OI is along $y$-axis; angle between OI and vertical: $\tan\theta = \frac{1}{2.7}$ or equivalent | A1 | |
| $\theta \approx 20.3°$ | A1 | |

---
3 A bracket is being made from a sheet of uniform thin metal. Firstly, a plate is cut from a square of the sheet metal in the shape OABCDEFHJK, shown shaded in Fig. 3.1. The dimensions shown in the figure are in centimetres; axes $\mathrm { O } x$ and $\mathrm { O } y$ are also shown.

\begin{figure}[h]
\begin{center}
  \includegraphics[alt={},max width=\textwidth]{1dd32b82-020e-45ef-8146-892197fd0985-4_561_569_429_788}
\captionsetup{labelformat=empty}
\caption{Fig. 3.1}
\end{center}
\end{figure}

(i) Show that, referred to the axes given in Fig. 3.1, the centre of mass of the plate OABCDEFHJK has coordinates (0.8, 2.5).

The plate is hung using light vertical strings attached to $\mathbf { J }$ and $\mathbf { H }$. The edge $\mathbf { J H }$ is horizontal and the plate is in equilibrium. The weight of the plate is 3.2 N .\\
(ii) Calculate the tensions in each of the strings.

The plate is now bent to form the bracket. This is shown in Fig. 3.2: the rectangle IJKO is folded along the line IA so that it is perpendicular to the plane ABCGHI ; the rectangle DEFG is folded along the line DG so it is also perpendicular to the plane ABCGHI but on the other side of it. Fig. 3.2 also shows the axes $\mathrm { O } x , \mathrm { O } y$ and $\mathrm { O } z$.

\begin{figure}[h]
\begin{center}
  \includegraphics[alt={},max width=\textwidth]{1dd32b82-020e-45ef-8146-892197fd0985-4_611_782_1713_678}
\captionsetup{labelformat=empty}
\caption{Fig. 3.2}
\end{center}
\end{figure}

(iii) Show that, referred to the axes given in Fig. 3.2, the centre of mass of the bracket has coordinates ( $1,2.7,0$ ).

The bracket is now hung freely in equilibrium from a string attached to O .\\
(iv) Calculate the angle between the edge OI and the vertical.

\hfill \mbox{\textit{OCR MEI M2 2011 Q3 [18]}}