OCR M2 2009 June — Question 2 8 marks

Exam BoardOCR
ModuleM2 (Mechanics 2)
Year2009
SessionJune
Marks8
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicPower and driving force
TypeMaximum speed on incline vs horizontal
DifficultyStandard +0.3 This is a straightforward M2 power question requiring standard application of P=Fv and F=ma with resistance forces. Part (i) is routine (P=Fv with resistance only), part (ii) adds a component force down the slope, and part (iii) requires resolving forces and finding acceleration. All steps follow standard procedures with no novel problem-solving required, making it slightly easier than average.
Spec3.03v Motion on rough surface: including inclined planes6.02l Power and velocity: P = Fv6.02m Variable force power: using scalar product

2 A car of mass 1100 kg has maximum power of 44000 W . The resistive forces have constant magnitude 1400 N .
  1. Calculate the maximum steady speed of the car on the level. The car is moving on a hill of constant inclination \(\alpha\) to the horizontal, where \(\sin \alpha = 0.05\).
  2. Calculate the maximum steady speed of the car when ascending the hill.
  3. Calculate the acceleration of the car when it is descending the hill at a speed of \(10 \mathrm {~m} \mathrm {~s} ^ { - 1 }\) working at half the maximum power.

2 A car of mass 1100 kg has maximum power of 44000 W . The resistive forces have constant magnitude 1400 N .\\
(i) Calculate the maximum steady speed of the car on the level.

The car is moving on a hill of constant inclination $\alpha$ to the horizontal, where $\sin \alpha = 0.05$.\\
(ii) Calculate the maximum steady speed of the car when ascending the hill.\\
(iii) Calculate the acceleration of the car when it is descending the hill at a speed of $10 \mathrm {~m} \mathrm {~s} ^ { - 1 }$ working at half the maximum power.

\hfill \mbox{\textit{OCR M2 2009 Q2 [8]}}