CAIE P2 Specimen — Question 2 5 marks

Exam BoardCAIE
ModuleP2 (Pure Mathematics 2)
SessionSpecimen
Marks5
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicProduct & Quotient Rules
TypePoints with specific gradient
DifficultyStandard +0.3 This is a straightforward application of the quotient rule followed by solving a simple equation. Students must differentiate the rational function, set dy/dx = -4, and solve for x-coordinates. While it requires multiple steps (differentiation, equation setup, algebraic manipulation), each step is routine and the question follows a standard template with no conceptual surprises.
Spec1.07m Tangents and normals: gradient and equations

2 A curve has equation $$y = \frac { 3 x + 1 } { x - 5 }$$ Find the coordinates of the points on the curve at which the gradient is - 4 .

Question 2:
AnswerMarks Guidance
AnswerMarks Guidance
Use quotient rule or, after adjustment, product ruleM1*
Obtain \(\frac{3x-15-3x-1}{(x-5)^2}\) or equivalentA1
Equate first derivative to \(-4\) and solve for \(x\)DM1
Obtain \(x\)-coordinates \(3\) and \(7\) or one correct pair of coordinatesA1
Obtain \(y\)-coordinates \(-5\) and \(11\) respectively or other correct pair of coordinatesA1
Total: 5
## Question 2:

| Answer | Marks | Guidance |
|--------|-------|----------|
| Use quotient rule or, after adjustment, product rule | M1* | |
| Obtain $\frac{3x-15-3x-1}{(x-5)^2}$ or equivalent | A1 | |
| Equate first derivative to $-4$ and solve for $x$ | DM1 | |
| Obtain $x$-coordinates $3$ and $7$ or one correct pair of coordinates | A1 | |
| Obtain $y$-coordinates $-5$ and $11$ respectively or other correct pair of coordinates | A1 | |
| **Total: 5** | | |

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2 A curve has equation

$$y = \frac { 3 x + 1 } { x - 5 }$$

Find the coordinates of the points on the curve at which the gradient is - 4 .\\

\hfill \mbox{\textit{CAIE P2  Q2 [5]}}