AQA M2 2011 June — Question 6 6 marks

Exam BoardAQA
ModuleM2 (Mechanics 2)
Year2011
SessionJune
Marks6
PaperDownload PDF ↗
TopicVariable Force
TypeAir resistance with other powers
DifficultyStandard +0.3 This is a standard M2 variable force question requiring Newton's second law followed by separating variables and integrating. The fractional power (5/4) makes the algebra slightly less routine than integer powers, but the method is entirely standard for this topic with clear signposting ('show that') at each stage.
Spec6.06a Variable force: dv/dt or v*dv/dx methods

6 A car, of mass \(m \mathrm {~kg}\), is moving along a straight horizontal road. At time \(t\) seconds, the car has speed \(v \mathrm {~m} \mathrm {~s} ^ { - 1 }\). As the car moves, it experiences a resistance force of magnitude \(2 m v ^ { \frac { 5 } { 4 } }\) newtons. No other horizontal force acts on the car.
  1. Show that $$\frac { \mathrm { d } v } { \mathrm {~d} t } = - 2 v ^ { \frac { 5 } { 4 } }$$ (1 mark)
  2. The initial speed of the car is \(16 \mathrm {~ms} ^ { - 1 }\). Show that $$v = \left( \frac { 2 } { t + 1 } \right) ^ { 4 }$$ (5 marks)

6 A car, of mass $m \mathrm {~kg}$, is moving along a straight horizontal road. At time $t$ seconds, the car has speed $v \mathrm {~m} \mathrm {~s} ^ { - 1 }$. As the car moves, it experiences a resistance force of magnitude $2 m v ^ { \frac { 5 } { 4 } }$ newtons. No other horizontal force acts on the car.
\begin{enumerate}[label=(\alph*)]
\item Show that

$$\frac { \mathrm { d } v } { \mathrm {~d} t } = - 2 v ^ { \frac { 5 } { 4 } }$$

(1 mark)
\item The initial speed of the car is $16 \mathrm {~ms} ^ { - 1 }$.

Show that

$$v = \left( \frac { 2 } { t + 1 } \right) ^ { 4 }$$

(5 marks)
\end{enumerate}

\hfill \mbox{\textit{AQA M2 2011 Q6 [6]}}