AQA M2 2011 June — Question 3 14 marks

Exam BoardAQA
ModuleM2 (Mechanics 2)
Year2011
SessionJune
Marks14
PaperDownload PDF ↗
TopicVariable acceleration (vectors)
TypeFind force using F=ma
DifficultyStandard +0.3 This is a straightforward M2 mechanics question requiring standard differentiation/integration of vector functions. Part (a) differentiates velocity to get acceleration, (b) applies F=ma, (c) solves when j-component is zero, and (d) integrates velocity with initial conditions. All techniques are routine for M2 students with no novel problem-solving required, making it slightly easier than average.
Spec1.08d Evaluate definite integrals: between limits3.02f Non-uniform acceleration: using differentiation and integration3.03d Newton's second law: 2D vectors

3 A particle moves in a horizontal plane under the action of a single force, \(\mathbf { F }\) newtons. The unit vectors \(\mathbf { i }\) and \(\mathbf { j }\) are directed east and north respectively. At time \(t\) seconds, the velocity of the particle, \(\mathbf { v } \mathrm { ms } ^ { - 1 }\), is given by $$\mathbf { v } = 4 \mathrm { e } ^ { - 2 t } \mathbf { i } + \left( 6 t - 3 t ^ { 2 } \right) \mathbf { j }$$
  1. Find an expression for the acceleration of the particle at time \(t\).
  2. The mass of the particle is 5 kg .
    1. Find an expression for the force \(\mathbf { F }\) acting on the particle at time \(t\).
    2. Find the magnitude of \(\mathbf { F }\) when \(t = 0\).
  3. Find the value of \(t\) when \(\mathbf { F }\) acts due west.
  4. When \(t = 0\), the particle is at the point with position vector \(( 6 \mathbf { i } + 5 \mathbf { j } ) \mathrm { m }\). Find the position vector, \(\mathbf { r }\) metres, of the particle at time \(t\).

3 A particle moves in a horizontal plane under the action of a single force, $\mathbf { F }$ newtons. The unit vectors $\mathbf { i }$ and $\mathbf { j }$ are directed east and north respectively. At time $t$ seconds, the velocity of the particle, $\mathbf { v } \mathrm { ms } ^ { - 1 }$, is given by

$$\mathbf { v } = 4 \mathrm { e } ^ { - 2 t } \mathbf { i } + \left( 6 t - 3 t ^ { 2 } \right) \mathbf { j }$$
\begin{enumerate}[label=(\alph*)]
\item Find an expression for the acceleration of the particle at time $t$.
\item The mass of the particle is 5 kg .
\begin{enumerate}[label=(\roman*)]
\item Find an expression for the force $\mathbf { F }$ acting on the particle at time $t$.
\item Find the magnitude of $\mathbf { F }$ when $t = 0$.
\end{enumerate}\item Find the value of $t$ when $\mathbf { F }$ acts due west.
\item When $t = 0$, the particle is at the point with position vector $( 6 \mathbf { i } + 5 \mathbf { j } ) \mathrm { m }$.

Find the position vector, $\mathbf { r }$ metres, of the particle at time $t$.
\end{enumerate}

\hfill \mbox{\textit{AQA M2 2011 Q3 [14]}}