OCR MEI M1 — Question 4 3 marks

Exam BoardOCR MEI
ModuleM1 (Mechanics 1)
Marks3
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicSUVAT in 2D & Gravity
TypeVertical projection: speed at given height
DifficultyEasy -1.2 This is a straightforward SUVAT application requiring only one equation (v² = u² + 2as) with clearly given values. It's a standard textbook exercise with no problem-solving insight needed, making it easier than average but not trivial since students must select the correct equation and handle the sign of acceleration.
Spec3.02d Constant acceleration: SUVAT formulae3.02h Motion under gravity: vector form

4 A pellet is fired vertically upwards at a speed of \(11 \mathrm {~ms} ^ { - 1 }\). Assuming that air resistance may be neglected, calculate the speed at which the pellet hits a ceiling 2.4 m above its point of projection.

Question 4:
AnswerMarks Guidance
AnswerMark Guidance
\(v^2 = 11^2 + 2\times(-9.8)\times2.4\)M1 Use of \(v^2 = u^2 + 2as\) or complete sequence of correct suvat. Accept sign errors in substitution
A1All correct
\(v = 8.6\) so \(8.6\ \text{ms}^{-1}\)A1 cao [Award all marks if 8.6 seen WWW] Do not condone \(\pm8.6\)
3
## Question 4:

| Answer | Mark | Guidance |
|--------|------|----------|
| $v^2 = 11^2 + 2\times(-9.8)\times2.4$ | M1 | Use of $v^2 = u^2 + 2as$ or complete sequence of correct suvat. Accept sign errors in substitution |
| | A1 | All correct |
| $v = 8.6$ so $8.6\ \text{ms}^{-1}$ | A1 | cao [Award all marks if 8.6 seen WWW] Do not condone $\pm8.6$ |
| | **3** | |

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4 A pellet is fired vertically upwards at a speed of $11 \mathrm {~ms} ^ { - 1 }$. Assuming that air resistance may be neglected, calculate the speed at which the pellet hits a ceiling 2.4 m above its point of projection.

\hfill \mbox{\textit{OCR MEI M1  Q4 [3]}}