Edexcel M1 — Question 3 9 marks

Exam BoardEdexcel
ModuleM1 (Mechanics 1)
Marks9
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicConstant acceleration (SUVAT)
TypeTime to reach midpoint or specific position
DifficultyStandard +0.3 Part (a) is a straightforward SUVAT calculation using s = (u+v)t/2. Part (b) requires solving a quadratic equation from s = ut + ½at², which is slightly beyond routine but still a standard M1 exercise. The 6-mark allocation and two-part structure make this slightly above average difficulty for typical mechanics questions.
Spec3.02d Constant acceleration: SUVAT formulae

3. A lorry accelerates uniformly from \(5 \mathrm {~m} \mathrm {~s} ^ { - 1 }\) to \(20 \mathrm {~m} \mathrm {~s} ^ { - 1 }\) in 30 seconds.
  1. Find how far it travels while accelerating.
  2. Find, in seconds correct to 2 decimal places, the length of time it takes for the lorry to cover the first half of this distance.
    (6 marks)

Question 3:
Part (a)
AnswerMarks Guidance
Answer/WorkingMarks Guidance
Use of \(s = \left(\frac{u+v}{2}\right)t\) with \(u=5\), \(v=20\) and \(t=30\)M1
\(s = \frac{25}{2} \times 30 = 375\) mM1 A1
Part (b)
AnswerMarks Guidance
Answer/WorkingMarks Guidance
\(a = \frac{\Delta v}{t} = \frac{20-5}{30} = 0.5\), \(s = 187.5\), \(u = 5\), use \(s = ut + \frac{1}{2}at^2\)M1 A1
\(187.5 = 5t + 0.25t^2 \therefore t^2 + 20t - 750 = 0\)M1
Use quadratic formula to give \(t = -10 \pm 5\sqrt{34}\)M1 A1
Take \(+\)ve root \(\therefore t = 19.15\) seconds (2dp)A1 (9)
## Question 3:

### Part (a)
| Answer/Working | Marks | Guidance |
|---|---|---|
| Use of $s = \left(\frac{u+v}{2}\right)t$ with $u=5$, $v=20$ and $t=30$ | M1 | |
| $s = \frac{25}{2} \times 30 = 375$ m | M1 A1 | |

### Part (b)
| Answer/Working | Marks | Guidance |
|---|---|---|
| $a = \frac{\Delta v}{t} = \frac{20-5}{30} = 0.5$, $s = 187.5$, $u = 5$, use $s = ut + \frac{1}{2}at^2$ | M1 A1 | |
| $187.5 = 5t + 0.25t^2 \therefore t^2 + 20t - 750 = 0$ | M1 | |
| Use quadratic formula to give $t = -10 \pm 5\sqrt{34}$ | M1 A1 | |
| Take $+$ve root $\therefore t = 19.15$ seconds (2dp) | A1 | **(9)** |

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3. A lorry accelerates uniformly from $5 \mathrm {~m} \mathrm {~s} ^ { - 1 }$ to $20 \mathrm {~m} \mathrm {~s} ^ { - 1 }$ in 30 seconds.
\begin{enumerate}[label=(\alph*)]
\item Find how far it travels while accelerating.
\item Find, in seconds correct to 2 decimal places, the length of time it takes for the lorry to cover the first half of this distance.\\
(6 marks)
\end{enumerate}

\hfill \mbox{\textit{Edexcel M1  Q3 [9]}}