Edexcel M1 — Question 1 6 marks

Exam BoardEdexcel
ModuleM1 (Mechanics 1)
Marks6
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicForces, equilibrium and resultants
TypeParticle with string at angle to wall
DifficultyEasy -1.2 This is a straightforward statics problem requiring resolution of forces in two directions with a simple geometry (30° angle). Part (a) involves basic trigonometry and equilibrium equations, while part (b) is essentially given once (a) is solved. Significantly easier than average A-level questions as it's a standard M1 exercise with no problem-solving insight required.
Spec1.05g Exact trigonometric values: for standard angles3.03e Resolve forces: two dimensions3.03m Equilibrium: sum of resolved forces = 03.03n Equilibrium in 2D: particle under forces

1. \begin{figure}[h]
\includegraphics[alt={},max width=\textwidth]{6fb27fe5-055a-4701-bd80-e66ebd57292a-2_403_550_214_609} \captionsetup{labelformat=empty} \caption{Fig. 1}
\end{figure} Figure 1 shows a light, inextensible string fixed at one end to a point \(P\). The other end is attached to a small object of weight 10 N . The object is subjected to a horizontal force \(H\) so that the string makes an angle of \(30 ^ { \circ }\) with the vertical.
  1. Find the magnitude of the tension in the string.
  2. Show that the ratio of the magnitude of the tension to the magnitude of \(H\) is \(2 : 1\).

Question 1:
Part (a)
AnswerMarks Guidance
Answer/WorkingMarks Guidance
Resolve \(\uparrow\): \(T\cos30 - W = 0\)M1
\(\frac{\sqrt{3}}{2}T = 10 \therefore T = \frac{20\sqrt{3}}{3} = 11.5\) N (3sf)M1 A1
Part (b)
AnswerMarks Guidance
Answer/WorkingMarks Guidance
Resolve \(\rightarrow\): \(H - T\sin30 = 0\)M1
\(H = \frac{1}{2}T\) so \(T:H = 1:\frac{1}{2} = 2:1\)M1 A1 (6)
## Question 1:

### Part (a)
| Answer/Working | Marks | Guidance |
|---|---|---|
| Resolve $\uparrow$: $T\cos30 - W = 0$ | M1 | |
| $\frac{\sqrt{3}}{2}T = 10 \therefore T = \frac{20\sqrt{3}}{3} = 11.5$ N (3sf) | M1 A1 | |

### Part (b)
| Answer/Working | Marks | Guidance |
|---|---|---|
| Resolve $\rightarrow$: $H - T\sin30 = 0$ | M1 | |
| $H = \frac{1}{2}T$ so $T:H = 1:\frac{1}{2} = 2:1$ | M1 A1 | **(6)** |

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1.

\begin{figure}[h]
\begin{center}
  \includegraphics[alt={},max width=\textwidth]{6fb27fe5-055a-4701-bd80-e66ebd57292a-2_403_550_214_609}
\captionsetup{labelformat=empty}
\caption{Fig. 1}
\end{center}
\end{figure}

Figure 1 shows a light, inextensible string fixed at one end to a point $P$. The other end is attached to a small object of weight 10 N . The object is subjected to a horizontal force $H$ so that the string makes an angle of $30 ^ { \circ }$ with the vertical.
\begin{enumerate}[label=(\alph*)]
\item Find the magnitude of the tension in the string.
\item Show that the ratio of the magnitude of the tension to the magnitude of $H$ is $2 : 1$.
\end{enumerate}

\hfill \mbox{\textit{Edexcel M1  Q1 [6]}}