Edexcel M1 — Question 3 9 marks

Exam BoardEdexcel
ModuleM1 (Mechanics 1)
Marks9
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicVectors Introduction & 2D
TypeParallel or perpendicular vectors condition
DifficultyModerate -0.3 This is a straightforward M1 mechanics question requiring basic vector operations: (a) finding magnitude at t=0 is simple substitution, (b) parallel vectors condition requires equating components (standard technique), (c) is a simple interpretation question. All parts are routine applications of standard methods with no novel problem-solving required, making it slightly easier than average.
Spec1.10c Magnitude and direction: of vectors1.10h Vectors in kinematics: uniform acceleration in vector form

3. In a simple model for the motion of a car, its velocity, \(\mathbf { v }\), at time \(t\) seconds, is given by $$\mathbf { v } = \left( 3 t ^ { 2 } - 2 t + 8 \right) \mathbf { i } + ( 5 t + 6 ) \mathbf { j } \mathrm { ms } ^ { - 1 }$$
  1. Calculate the speed of the car when \(t = 0\).
  2. Find the values of \(t\) for which the velocity of the car is parallel to the vector \(( \mathbf { i } + \mathbf { j } )\).
  3. Why would this model not be appropriate for large values of \(t\) ?

AnswerMarks Guidance
(a) \(t = 0 \Rightarrow \mathbf{v} = 8\mathbf{i} + 6\mathbf{j}\)M1
speed = \(\sqrt{8^2 + 6^2} = 10 \text{ ms}^{-1}\)M1 A1
(b) parallel to \((\mathbf{i} + \mathbf{j})\) when \(3t^2 - 2t + 8 = 5t + 6\)M1
i.e. \(3t^2 - 7t + 2 = 0\)A1
\((3t - 1)(t - 2) = 0\)M1 A1
\(t = \frac{1}{3}\) or 2A1
(c) e.g. improbably large values for the speed of the carB1 (9)
(a) $t = 0 \Rightarrow \mathbf{v} = 8\mathbf{i} + 6\mathbf{j}$ | M1 |
speed = $\sqrt{8^2 + 6^2} = 10 \text{ ms}^{-1}$ | M1 A1 |

(b) parallel to $(\mathbf{i} + \mathbf{j})$ when $3t^2 - 2t + 8 = 5t + 6$ | M1 |
i.e. $3t^2 - 7t + 2 = 0$ | A1 |
$(3t - 1)(t - 2) = 0$ | M1 A1 |
$t = \frac{1}{3}$ or 2 | A1 |

(c) e.g. improbably large values for the speed of the car | B1 | (9) |
3. In a simple model for the motion of a car, its velocity, $\mathbf { v }$, at time $t$ seconds, is given by

$$\mathbf { v } = \left( 3 t ^ { 2 } - 2 t + 8 \right) \mathbf { i } + ( 5 t + 6 ) \mathbf { j } \mathrm { ms } ^ { - 1 }$$
\begin{enumerate}[label=(\alph*)]
\item Calculate the speed of the car when $t = 0$.
\item Find the values of $t$ for which the velocity of the car is parallel to the vector $( \mathbf { i } + \mathbf { j } )$.
\item Why would this model not be appropriate for large values of $t$ ?
\end{enumerate}

\hfill \mbox{\textit{Edexcel M1  Q3 [9]}}