Edexcel M1 — Question 1 8 marks

Exam BoardEdexcel
ModuleM1 (Mechanics 1)
Marks8
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicConstant acceleration (SUVAT)
TypeAverage speed or total distance calculation
DifficultyModerate -0.8 This is a straightforward mechanics question requiring basic ratio and average speed calculations. Students need to set up simple equations using distance = speed × time, with no conceptual challenges beyond understanding that the stop is excluded from part (b). The multi-part structure and algebraic manipulation are routine for M1 level.
Spec3.02a Kinematics language: position, displacement, velocity, acceleration

1. \begin{figure}[h]
\includegraphics[alt={},max width=\textwidth]{8a0ff401-83da-4539-a9e9-68736c57df2a-2_520_1278_207_333} \captionsetup{labelformat=empty} \caption{Fig. 1}
\end{figure} Figure 1 shows a distance-time graph for a car journey from Birmingham to Newquay which included a stop for lunch at a service station near Exeter. During the first part of the journey three-quarters of the total distance, \(d\), was covered in 3 hours. After a 1 hour stop, the remaining distance was completed in 2 hours.
  1. Calculate, in the form \(k : 1\), the ratio of the average speed during the first 3 hours of the journey to the average speed during the last 2 hours of the journey.
    (4 marks)
    Given that the average speed of the car over the whole journey (excluding the stop) was \(80 \mathrm { kmh } ^ { - 1 }\),
  2. find the average speed of the car on the first part of the journey.
    (4 marks)

AnswerMarks Guidance
(a) ratio is \(\frac{1}{3}d : \frac{1}{2}d\)M1 A1
\(= \frac{1}{4} : \frac{1}{8} = 2:1\)M1 A1
(b) \(80 \text{ kmh}^{-1}\) for 5 hrs = 400 kmM1
\(\frac{3}{4}\) of 400 = 300 kmM1
av. speed on first part of journey = \(\frac{300}{3} = 100 \text{ kmh}^{-1}\)M1 A1 (8)
(a) ratio is $\frac{1}{3}d : \frac{1}{2}d$ | M1 A1 |
$= \frac{1}{4} : \frac{1}{8} = 2:1$ | M1 A1 |

(b) $80 \text{ kmh}^{-1}$ for 5 hrs = 400 km | M1 |
$\frac{3}{4}$ of 400 = 300 km | M1 |
av. speed on first part of journey = $\frac{300}{3} = 100 \text{ kmh}^{-1}$ | M1 A1 | (8) |
1.

\begin{figure}[h]
\begin{center}
  \includegraphics[alt={},max width=\textwidth]{8a0ff401-83da-4539-a9e9-68736c57df2a-2_520_1278_207_333}
\captionsetup{labelformat=empty}
\caption{Fig. 1}
\end{center}
\end{figure}

Figure 1 shows a distance-time graph for a car journey from Birmingham to Newquay which included a stop for lunch at a service station near Exeter. During the first part of the journey three-quarters of the total distance, $d$, was covered in 3 hours. After a 1 hour stop, the remaining distance was completed in 2 hours.
\begin{enumerate}[label=(\alph*)]
\item Calculate, in the form $k : 1$, the ratio of the average speed during the first 3 hours of the journey to the average speed during the last 2 hours of the journey.\\
(4 marks)\\
Given that the average speed of the car over the whole journey (excluding the stop) was $80 \mathrm { kmh } ^ { - 1 }$,
\item find the average speed of the car on the first part of the journey.\\
(4 marks)
\end{enumerate}

\hfill \mbox{\textit{Edexcel M1  Q1 [8]}}