| Exam Board | AQA |
|---|---|
| Module | M1 (Mechanics 1) |
| Year | 2014 |
| Session | June |
| Marks | 9 |
| Paper | Download PDF ↗ |
| Mark scheme | Download PDF ↗ |
| Topic | Constant acceleration (SUVAT) |
| Type | SUVAT single equation: straightforward find |
| Difficulty | Moderate -0.8 This is a straightforward three-part SUVAT and Newton's second law question requiring only direct application of standard formulas (v=u+at, s=ut+½at², F=ma). Each part follows mechanically from given values with no problem-solving insight needed, making it easier than average but not trivial due to the multi-step nature and force calculation. |
| Spec | 3.02d Constant acceleration: SUVAT formulae3.03c Newton's second law: F=ma one dimension3.03f Weight: W=mg |
| Answer | Marks | Guidance |
|---|---|---|
| \(v = 14 + 0.8 \times 12\) | M1 | Use of \(v = u + at\) with correct values |
| \(v = 23.6 \text{ m s}^{-1}\) | A1 | |
| A1 | cao |
| Answer | Marks | Guidance |
|---|---|---|
| \(s = 14 \times 12 + \frac{1}{2} \times 0.8 \times 12^2\) | M1 | Use of \(s = ut + \frac{1}{2}at^2\) or equivalent |
| A1 | Correct substitution | |
| \(s = 168 + 57.6 = 225.6 \text{ m}\) | A1 | cao |
| Answer | Marks | Guidance |
|---|---|---|
| \(F_{net} = 1400 \times 0.8 = 1120 \text{ N}\) | M1 | Use of \(F = ma\) |
| \(R = 1600 - 1120\) | M1 | Subtract from driving force |
| \(R = 480 \text{ N}\) | A1 | cao |
# Question 1:
## Part (a)
| $v = 14 + 0.8 \times 12$ | M1 | Use of $v = u + at$ with correct values |
|---|---|---|
| $v = 23.6 \text{ m s}^{-1}$ | A1 | |
| | A1 | cao |
## Part (b)
| $s = 14 \times 12 + \frac{1}{2} \times 0.8 \times 12^2$ | M1 | Use of $s = ut + \frac{1}{2}at^2$ or equivalent |
|---|---|---|
| | A1 | Correct substitution |
| $s = 168 + 57.6 = 225.6 \text{ m}$ | A1 | cao |
## Part (c)
| $F_{net} = 1400 \times 0.8 = 1120 \text{ N}$ | M1 | Use of $F = ma$ |
|---|---|---|
| $R = 1600 - 1120$ | M1 | Subtract from driving force |
| $R = 480 \text{ N}$ | A1 | cao |
---1 A car is travelling along a straight horizontal road. It is moving at $14 \mathrm {~m} \mathrm {~s} ^ { - 1 }$ when it starts to accelerate. It accelerates at $0.8 \mathrm {~m} \mathrm {~s} ^ { - 2 }$ for 12 seconds.
\begin{enumerate}[label=(\alph*)]
\item Find the speed of the car at the end of the 12 seconds.
\item Find the distance travelled during the 12 seconds.
\item The mass of the car is 1400 kg . A horizontal forward driving force of 1600 N acts on the car during the 12 seconds. Find the magnitude of the resistance force that acts on the car.\\[0pt]
[3 marks]
\begin{center}
\includegraphics[max width=\textwidth, alt={}]{788534a5-abbb-4d6a-87b2-c54e859a128a-02_1513_1709_1192_153}
\end{center}
\end{enumerate}
\hfill \mbox{\textit{AQA M1 2014 Q1 [9]}}