| Exam Board | AQA |
|---|---|
| Module | M1 (Mechanics 1) |
| Year | 2009 |
| Session | June |
| Marks | 6 |
| Paper | Download PDF ↗ |
| Mark scheme | Download PDF ↗ |
| Topic | Constant acceleration (SUVAT) |
| Type | SUVAT simultaneous equations: find u and a |
| Difficulty | Moderate -0.8 This is a straightforward two-part SUVAT question requiring direct application of kinematic equations with given values. Part (a) uses s = (u+v)t/2 to find u, and part (b) uses v = u + at to find acceleration. Both are standard textbook exercises with no problem-solving insight required, making it easier than average but not trivial since it involves algebraic manipulation. |
| Spec | 3.02d Constant acceleration: SUVAT formulae |
| Answer | Marks | Guidance |
|---|---|---|
| Answer | Mark | Guidance |
| Using \(s = \frac{1}{2}(u+v)t\): \(16 = \frac{1}{2}(u + 4.2)(5)\) | M1 | Correct use of suvat with \(s=16\), \(v=4.2\), \(t=5\) |
| \(16 = \frac{5}{2}(u + 4.2)\) | M1 | Correct equation formed |
| \(u = 2.2\) m s\(^{-1}\) | A1 | cao |
| Answer | Marks | Guidance |
|---|---|---|
| Answer | Mark | Guidance |
| Using \(v = u + at\): \(4.2 = 2.2 + 5a\) | M1 | Correct suvat equation with their \(u\) |
| \(a = \frac{4.2-2.2}{5}\) | M1 | Rearranging to find \(a\) |
| \(a = 0.4\) m s\(^{-2}\) | A1 | cao |
# Question 2:
## Part (a)
| Answer | Mark | Guidance |
|--------|------|----------|
| Using $s = \frac{1}{2}(u+v)t$: $16 = \frac{1}{2}(u + 4.2)(5)$ | M1 | Correct use of suvat with $s=16$, $v=4.2$, $t=5$ |
| $16 = \frac{5}{2}(u + 4.2)$ | M1 | Correct equation formed |
| $u = 2.2$ m s$^{-1}$ | A1 | cao |
## Part (b)
| Answer | Mark | Guidance |
|--------|------|----------|
| Using $v = u + at$: $4.2 = 2.2 + 5a$ | M1 | Correct suvat equation with their $u$ |
| $a = \frac{4.2-2.2}{5}$ | M1 | Rearranging to find $a$ |
| $a = 0.4$ m s$^{-2}$ | A1 | cao |
---2 A lift is travelling upwards and accelerating uniformly. During a 5 second period, it travels 16 metres and the speed of the lift increases from $u \mathrm {~m} \mathrm {~s} ^ { - 1 }$ to $4.2 \mathrm {~m} \mathrm {~s} ^ { - 1 }$.
\begin{enumerate}[label=(\alph*)]
\item $\quad$ Find $u$.
\item Find the acceleration of the lift.
\end{enumerate}
\hfill \mbox{\textit{AQA M1 2009 Q2 [6]}}