CAIE P2 2017 November — Question 3 7 marks

Exam BoardCAIE
ModuleP2 (Pure Mathematics 2)
Year2017
SessionNovember
Marks7
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicInequalities
TypeCombined linear and quadratic inequalities
DifficultyStandard +0.3 This question combines exponential and modulus inequalities, both standard P2 topics. The exponential inequality requires straightforward logarithm application, while the modulus inequality solves by squaring both sides or considering cases. The combination and intersection of solutions adds mild complexity, but each component uses routine techniques with no novel insight required.
Spec1.02l Modulus function: notation, relations, equations and inequalities1.06g Equations with exponentials: solve a^x = b

3 It is given that the variable \(x\) is such that $$1.3 ^ { 2 x } < 80 \quad \text { and } \quad | 3 x - 1 | > | 3 x - 10 | .$$ Find the set of possible values of \(x\), giving your answer in the form \(a < x < b\) where the constants \(a\) and \(b\) are correct to 3 significant figures.

Question 3:
AnswerMarks Guidance
AnswerMarks Guidance
Take logarithms of both sides and apply power lawM1 Condone incorrect inequality signs until final answer. The first 6 marks are for obtaining the correct critical values.
Obtain \(2x < \frac{\ln 80}{\ln 1.3}\) or equivalent using \(\log_{10}\)A1
Obtain \(x = 8.35...\)A1
State or imply non-modulus inequality \((3x-1)^2 > (3x-10)^2\) or corresponding equation or linear equation \(3x-1 = -(3x-10)\)B1
Attempt solution of inequality or equation (obtaining 3 terms when squaring each bracket or solving linear equation with signs of \(3x\) different)M1
Obtain \(x = \frac{11}{6}\) or \(x = 1.83...\)A1
Conclude \(1.83 < x < 8.35\)A1
## Question 3:

| Answer | Marks | Guidance |
|--------|-------|----------|
| Take logarithms of both sides and apply power law | M1 | Condone incorrect inequality signs until final answer. The first 6 marks are for obtaining the correct critical values. |
| Obtain $2x < \frac{\ln 80}{\ln 1.3}$ or equivalent using $\log_{10}$ | A1 | |
| Obtain $x = 8.35...$ | A1 | |
| State or imply non-modulus inequality $(3x-1)^2 > (3x-10)^2$ or corresponding equation or linear equation $3x-1 = -(3x-10)$ | B1 | |
| Attempt solution of inequality or equation (obtaining 3 terms when squaring each bracket or solving linear equation with signs of $3x$ different) | M1 | |
| Obtain $x = \frac{11}{6}$ or $x = 1.83...$ | A1 | |
| Conclude $1.83 < x < 8.35$ | A1 | |

---
3 It is given that the variable $x$ is such that

$$1.3 ^ { 2 x } < 80 \quad \text { and } \quad | 3 x - 1 | > | 3 x - 10 | .$$

Find the set of possible values of $x$, giving your answer in the form $a < x < b$ where the constants $a$ and $b$ are correct to 3 significant figures.\\

\hfill \mbox{\textit{CAIE P2 2017 Q3 [7]}}