Edexcel S4 2006 January — Question 1 8 marks

Exam BoardEdexcel
ModuleS4 (Statistics 4)
Year2006
SessionJanuary
Marks8
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicF-test and chi-squared for variance
TypeChi-squared confidence interval for variance
DifficultyStandard +0.3 This is a straightforward application of chi-squared confidence intervals for variance with clear steps: calculate sample variance, look up chi-squared critical values, and apply the standard formula. The interpretation in part (c) is routine. Slightly above average difficulty due to the S4 Further Maths context and chi-squared distribution being less familiar than normal/t-distributions, but the question is entirely procedural with no conceptual challenges.
Spec5.05b Unbiased estimates: of population mean and variance

  1. A diabetic patient records her blood glucose readings in \(\mathrm { mmol } / \mathrm { l }\) at random times of day over several days. Her readings are given below.
$$\begin{array} { l l l l l l l } 5.3 & 5.7 & 8.4 & 8.7 & 6.3 & 8.0 & 7.2 \end{array}$$ Assuming that the blood glucose readings are normally distributed calculate
  1. an unbiased estimate for the variance \(\sigma ^ { 2 }\) of the blood glucose readings,
  2. a \(90 \%\) confidence interval for the variance \(\sigma ^ { 2 }\) of blood glucose readings.
  3. State whether or not the confidence interval supports the assertion that \(\sigma = 0.9\). Give a reason for your answer.

\begin{enumerate}
  \item A diabetic patient records her blood glucose readings in $\mathrm { mmol } / \mathrm { l }$ at random times of day over several days. Her readings are given below.
\end{enumerate}

$$\begin{array} { l l l l l l l } 
5.3 & 5.7 & 8.4 & 8.7 & 6.3 & 8.0 & 7.2
\end{array}$$

Assuming that the blood glucose readings are normally distributed calculate\\
(a) an unbiased estimate for the variance $\sigma ^ { 2 }$ of the blood glucose readings,\\
(b) a $90 \%$ confidence interval for the variance $\sigma ^ { 2 }$ of blood glucose readings.\\
(c) State whether or not the confidence interval supports the assertion that $\sigma = 0.9$.

Give a reason for your answer.\\

\hfill \mbox{\textit{Edexcel S4 2006 Q1 [8]}}