Edexcel S2 — Question 1 7 marks

Exam BoardEdexcel
ModuleS2 (Statistics 2)
Marks7
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicPoisson distribution
TypeSingle time period probability
DifficultyEasy -1.2 This is a straightforward recall and calculation question requiring only direct application of standard distribution formulas or tables. Part (a) involves summing Poisson probabilities P(X=0) through P(X=3) using the given mean, while part (b) requires looking up or calculating a cumulative binomial probability. No problem-solving, interpretation, or conceptual understanding beyond basic definitions is needed—purely mechanical computation typical of early S2 exercises.
Spec5.02b Expectation and variance: discrete random variables5.02c Linear coding: effects on mean and variance5.02i Poisson distribution: random events model5.02j Poisson formula: P(X=x) = e^(-lambda)*lambda^x/x!5.02k Calculate Poisson probabilities

  1. (a) The random variable \(X\) follows a Poisson distribution with a mean of 1.4
Find \(\mathrm { P } ( X \leq 3 )\).
(b) The random variable \(Y\) follows a binomial distribution such that \(Y \sim \mathrm {~B} ( 20,0.6 )\). Find \(\mathrm { P } ( Y \leq 12 )\).
(4 marks)

AnswerMarks
\(e^{-1.4}(1 + 1.4 + \frac{1.4^2}{1!} + \frac{1.4^3}{3!})\)M1 A1
\(= 0.9463\) (4sf)A1
Let \(A \sim B(20, 0.4)\)M1
\(P(Y \leq 12) = P(A \geq 8)\)M1
\(= 1 - P(A \leq 7)\)M1
\(= 1 - 0.4159 = 0.5841\)A1
$e^{-1.4}(1 + 1.4 + \frac{1.4^2}{1!} + \frac{1.4^3}{3!})$ | M1 A1 | 
$= 0.9463$ (4sf) | A1 | 

Let $A \sim B(20, 0.4)$ | M1 | 
$P(Y \leq 12) = P(A \geq 8)$ | M1 | 
$= 1 - P(A \leq 7)$ | M1 | 
$= 1 - 0.4159 = 0.5841$ | A1 | 

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\begin{enumerate}
  \item (a) The random variable $X$ follows a Poisson distribution with a mean of 1.4
\end{enumerate}

Find $\mathrm { P } ( X \leq 3 )$.\\
(b) The random variable $Y$ follows a binomial distribution such that $Y \sim \mathrm {~B} ( 20,0.6 )$.

Find $\mathrm { P } ( Y \leq 12 )$.\\
(4 marks)\\

\hfill \mbox{\textit{Edexcel S2  Q1 [7]}}