Edexcel S2 — Question 2 6 marks

Exam BoardEdexcel
ModuleS2 (Statistics 2)
Marks6
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicContinuous Uniform Random Variables
TypeFind constant k in PDF
DifficultyEasy -1.3 This is a straightforward application of the basic property that a PDF must integrate to 1, requiring only simple integration of a constant over an interval. Part (a) involves elementary algebra (k × 10 = 1), and part (b) is direct substitution into the uniform CDF. This is below average difficulty as it tests only definitional knowledge with minimal calculation.
Spec5.03a Continuous random variables: pdf and cdf5.03e Find cdf: by integration

2. A continuous random variable \(X\) has the probability density function $$\begin{array} { l l } \mathrm { f } ( x ) = k & 5 \leq x \leq 15 , \\ \mathrm { f } ( x ) = 0 & \text { otherwise. } \end{array}$$
  1. Find \(k\) and specify the cumulative density function \(\mathrm { F } ( x )\).
  2. Write down the value of \(\mathrm { P } ( X < 8 )\).

AnswerMarks
(a) \(k = \frac{1}{10}\), so \(F(x) = 0\) \((x < 5)\), \(F(x) = \frac{x-5}{10}\) \((5 \le x \le 15)\), \(F(x) = 1\) \((x > 15)\)B1 B1 M1 A1
(b) \(P(X < 8) = F(8) = \frac{3}{10}\)B1
Total: 6 marks
(a) $k = \frac{1}{10}$, so $F(x) = 0$ $(x < 5)$, $F(x) = \frac{x-5}{10}$ $(5 \le x \le 15)$, $F(x) = 1$ $(x > 15)$ | B1 B1 M1 A1 |
(b) $P(X < 8) = F(8) = \frac{3}{10}$ | B1 |

**Total: 6 marks**
2. A continuous random variable $X$ has the probability density function

$$\begin{array} { l l } 
\mathrm { f } ( x ) = k & 5 \leq x \leq 15 , \\
\mathrm { f } ( x ) = 0 & \text { otherwise. }
\end{array}$$
\begin{enumerate}[label=(\alph*)]
\item Find $k$ and specify the cumulative density function $\mathrm { F } ( x )$.
\item Write down the value of $\mathrm { P } ( X < 8 )$.
\end{enumerate}

\hfill \mbox{\textit{Edexcel S2  Q2 [6]}}