AQA S2 2008 January — Question 7 19 marks

Exam BoardAQA
ModuleS2 (Statistics 2)
Year2008
SessionJanuary
Marks19
PaperDownload PDF ↗
TopicCumulative distribution functions
TypeFind quantiles from CDF
DifficultyModerate -0.3 This is a standard S2 question on CDFs and PDFs requiring routine techniques: reading quartiles from a CDF, verifying values by substitution, differentiating to find the PDF, and computing an expectation. While multi-part with several marks, each step follows textbook procedures with no novel problem-solving or conceptual difficulty beyond typical A-level statistics.
Spec5.03a Continuous random variables: pdf and cdf5.03e Find cdf: by integration5.03f Relate pdf-cdf: medians and percentiles

7 The waiting time, \(X\) minutes, for fans to gain entrance to see an event may be modelled by a continuous random variable having the distribution function defined by $$\mathrm { F } ( x ) = \begin{cases} 0 & x < 0 \\ \frac { 1 } { 2 } x & 0 \leqslant x \leqslant 1 \\ \frac { 1 } { 54 } \left( x ^ { 3 } - 12 x ^ { 2 } + 48 x - 10 \right) & 1 \leqslant x \leqslant 4 \\ 1 & x > 4 \end{cases}$$
    1. Sketch the graph of F.
    2. Explain why the value of \(q _ { 1 }\), the lower quartile of \(X\), is \(\frac { 1 } { 2 }\).
    3. Show that the upper quartile, \(q _ { 3 }\), satisfies \(1.6 < q _ { 3 } < 1.7\).
  1. The probability density function of \(X\) is defined by $$\mathrm { f } ( x ) = \begin{cases} \alpha & 0 \leqslant x \leqslant 1 \\ \beta ( x - 4 ) ^ { 2 } & 1 \leqslant x \leqslant 4 \\ 0 & \text { otherwise } \end{cases}$$
    1. Show that the exact values of \(\alpha\) and \(\beta\) are \(\frac { 1 } { 2 }\) and \(\frac { 1 } { 18 }\) respectively.
    2. Hence calculate \(\mathrm { E } ( X )\).

7 The waiting time, $X$ minutes, for fans to gain entrance to see an event may be modelled by a continuous random variable having the distribution function defined by

$$\mathrm { F } ( x ) = \begin{cases} 0 & x < 0 \\ \frac { 1 } { 2 } x & 0 \leqslant x \leqslant 1 \\ \frac { 1 } { 54 } \left( x ^ { 3 } - 12 x ^ { 2 } + 48 x - 10 \right) & 1 \leqslant x \leqslant 4 \\ 1 & x > 4 \end{cases}$$
\begin{enumerate}[label=(\alph*)]
\item \begin{enumerate}[label=(\roman*)]
\item Sketch the graph of F.
\item Explain why the value of $q _ { 1 }$, the lower quartile of $X$, is $\frac { 1 } { 2 }$.
\item Show that the upper quartile, $q _ { 3 }$, satisfies $1.6 < q _ { 3 } < 1.7$.
\end{enumerate}\item The probability density function of $X$ is defined by

$$\mathrm { f } ( x ) = \begin{cases} \alpha & 0 \leqslant x \leqslant 1 \\ \beta ( x - 4 ) ^ { 2 } & 1 \leqslant x \leqslant 4 \\ 0 & \text { otherwise } \end{cases}$$
\begin{enumerate}[label=(\roman*)]
\item Show that the exact values of $\alpha$ and $\beta$ are $\frac { 1 } { 2 }$ and $\frac { 1 } { 18 }$ respectively.
\item Hence calculate $\mathrm { E } ( X )$.
\end{enumerate}\end{enumerate}

\hfill \mbox{\textit{AQA S2 2008 Q7 [19]}}