Edexcel S1 — Question 2 10 marks

Exam BoardEdexcel
ModuleS1 (Statistics 1)
Marks10
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicDiscrete Probability Distributions
TypeTwo unknowns from sum and expectation
DifficultyModerate -0.3 This is a standard S1 probability distribution question requiring systematic application of two fundamental properties: probabilities sum to 1 and the expectation formula. While it involves solving simultaneous equations with two unknowns, the algebraic manipulation is straightforward and the approach is routine for this topic. Slightly easier than average due to the mechanical nature of the solution.
Spec5.02a Discrete probability distributions: general5.02b Expectation and variance: discrete random variables

2. The discrete random variable \(X\) has the following probability distribution.
\(x\)12345
\(\mathrm { P } ( X = x )\)\(a\)\(b\)\(\frac { 1 } { 4 }\)\(2 a\)\(\frac { 1 } { 8 }\)
  1. Find an expression for \(b\) in terms of \(a\).
  2. Find an expression for \(\mathrm { E } ( X )\) in terms of \(a\). Given that \(\mathrm { E } ( X ) = \frac { 45 } { 16 }\),
  3. find the values of \(a\) and \(b\),

Part (a)
AnswerMarks
\(a + b + \frac{1}{4} + 2a + \frac{1}{8} = 1\)M1
\(3a + b = \frac{5}{8}\); \(b = \frac{5}{8} - 3a\)M1 A1
Part (b)
AnswerMarks
\(\sum xP(x) = a + 2b + \frac{1}{4} + 8a + \frac{5}{8}\)M1
\(= 9a + 2(\frac{5}{8} - 3a) + \frac{11}{8} = 3a + \frac{21}{8}\)M1 A1
Part (c)
AnswerMarks
\(3a + \frac{21}{8} = \frac{45}{16}\)M1
\(3a = \frac{45}{16} - \frac{21}{8} = \frac{3}{16}\)M1
\(a = \frac{1}{16}, b = \frac{7}{16}\)A2
(10)
**Part (a)**

$a + b + \frac{1}{4} + 2a + \frac{1}{8} = 1$ | M1 |

$3a + b = \frac{5}{8}$; $b = \frac{5}{8} - 3a$ | M1 A1 |

**Part (b)**

$\sum xP(x) = a + 2b + \frac{1}{4} + 8a + \frac{5}{8}$ | M1 |

$= 9a + 2(\frac{5}{8} - 3a) + \frac{11}{8} = 3a + \frac{21}{8}$ | M1 A1 |

**Part (c)**

$3a + \frac{21}{8} = \frac{45}{16}$ | M1 |

$3a = \frac{45}{16} - \frac{21}{8} = \frac{3}{16}$ | M1 |

$a = \frac{1}{16}, b = \frac{7}{16}$ | A2 |

| (10) |
2. The discrete random variable $X$ has the following probability distribution.

\begin{center}
\begin{tabular}{ | c | c | c | c | c | c | }
\hline
$x$ & 1 & 2 & 3 & 4 & 5 \\
\hline
$\mathrm { P } ( X = x )$ & $a$ & $b$ & $\frac { 1 } { 4 }$ & $2 a$ & $\frac { 1 } { 8 }$ \\
\hline
\end{tabular}
\end{center}
\begin{enumerate}[label=(\alph*)]
\item Find an expression for $b$ in terms of $a$.
\item Find an expression for $\mathrm { E } ( X )$ in terms of $a$.

Given that $\mathrm { E } ( X ) = \frac { 45 } { 16 }$,
\item find the values of $a$ and $b$,
\end{enumerate}

\hfill \mbox{\textit{Edexcel S1  Q2 [10]}}