Edexcel S1 — Question 4 9 marks

Exam BoardEdexcel
ModuleS1 (Statistics 1)
Marks9
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicMeasures of Location and Spread
TypeCalculate statistics from raw data
DifficultyModerate -0.8 This is a straightforward S1 question requiring standard calculations of summary statistics from given data and applying linear transformations. The median requires simple counting, mean and standard deviation use provided sums with standard formulas, and part (b) applies well-known transformation rules. All techniques are routine textbook exercises with no problem-solving or conceptual challenges.
Spec2.02f Measures of average and spread2.02g Calculate mean and standard deviation

4. The marks, \(x\) out of 100 , scored by 30 candidates in an examination were as follows:
5192021232531373941
42444751565760616265
677071737577818298100
Given that \(\sum x = 1600\) and \(\sum x ^ { 2 } = 102400\),
  1. find the median, the mean and the standard deviation of these marks. The marks were scaled to give modified scores, \(y\), using the formula \(y = \frac { 4 x } { 5 } + 20\).
  2. Find the median, the mean and the standard deviation of the modified scores. \section*{STATISTICS 1 (A) TEST PAPER 1 Page 2}

AnswerMarks Guidance
(a) Median = \(56.5\)B1 B1
Mean = \(\frac{1600}{30} = 53\frac{1}{3}\)M1 A1 A1
Var = \(\frac{102400}{30} - \left(\frac{1600}{30}\right)^2 = 568.89\), so s.d. = \(23.9\)
(b) Median = \(65.2\), mean = \(62\frac{2}{3}\), variance = \(0.8 \times 23.9 = 19.1\)B1 B1 M1 A1 Total: 9 marks
(a) Median = $56.5$ | B1 B1 |

Mean = $\frac{1600}{30} = 53\frac{1}{3}$ | M1 A1 A1 |

Var = $\frac{102400}{30} - \left(\frac{1600}{30}\right)^2 = 568.89$, so s.d. = $23.9$ | 

(b) Median = $65.2$, mean = $62\frac{2}{3}$, variance = $0.8 \times 23.9 = 19.1$ | B1 B1 M1 A1 | **Total: 9 marks**
4. The marks, $x$ out of 100 , scored by 30 candidates in an examination were as follows:

\begin{center}
\begin{tabular}{ | r r r r r r r r r r | }
\hline
5 & 19 & 20 & 21 & 23 & 25 & 31 & 37 & 39 & 41 \\
42 & 44 & 47 & 51 & 56 & 57 & 60 & 61 & 62 & 65 \\
67 & 70 & 71 & 73 & 75 & 77 & 81 & 82 & 98 & 100 \\
\hline
\end{tabular}
\end{center}

Given that $\sum x = 1600$ and $\sum x ^ { 2 } = 102400$,
\begin{enumerate}[label=(\alph*)]
\item find the median, the mean and the standard deviation of these marks.

The marks were scaled to give modified scores, $y$, using the formula $y = \frac { 4 x } { 5 } + 20$.
\item Find the median, the mean and the standard deviation of the modified scores.

\section*{STATISTICS 1 (A) TEST PAPER 1 Page 2}
\end{enumerate}

\hfill \mbox{\textit{Edexcel S1  Q4 [9]}}