Edexcel S1 — Question 2 7 marks

Exam BoardEdexcel
ModuleS1 (Statistics 1)
Marks7
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicIndependent Events
TypeFind unknown probability given independence
DifficultyModerate -0.8 This is a straightforward application of independence (P(A∩B) = P(A)P(B)) and basic probability rules. Part (a) requires simple division, parts (b-d) use standard formulas with no conceptual challenges. It's routine S1 bookwork testing recall rather than problem-solving, making it easier than average.
Spec2.03a Mutually exclusive and independent events2.03b Probability diagrams: tree, Venn, sample space

2. The events \(A\) and \(B\) are independent. Given that \(\mathrm { P } ( A ) = 0.4\) and \(\mathrm { P } ( A \cap B ) = 0.12\), find
  1. \(\mathrm { P } ( B )\),
  2. \(\mathrm { P } ( A \cup B )\),
  3. \(\mathrm { P } \left( A ^ { \prime } \cap B \right)\),
  4. \(\mathrm { P } \left( A \mid B ^ { \prime } \right)\).

AnswerMarks Guidance
(a) \(P(B) = 0.12 + 0.4 = 0.3\)M1 A1
(b) \(P(A \cup B) = 0.7 - 0.12 = 0.58\)M1 A1
(c) \(P(A' \cap B) = 0.3 - 0.12 = 0.18\)M1 A1
(d) \(P(AB') = P(A) = 0.4\) M1 A1; B1
(a) $P(B) = 0.12 + 0.4 = 0.3$ | M1 A1 |

(b) $P(A \cup B) = 0.7 - 0.12 = 0.58$ | M1 A1 |

(c) $P(A' \cap B) = 0.3 - 0.12 = 0.18$ | M1 A1 |

(d) $P(A|B') = P(A) = 0.4$ | M1 A1; B1 | **Total: 7 marks**
2. The events $A$ and $B$ are independent. Given that $\mathrm { P } ( A ) = 0.4$ and $\mathrm { P } ( A \cap B ) = 0.12$, find
\begin{enumerate}[label=(\alph*)]
\item $\mathrm { P } ( B )$,
\item $\mathrm { P } ( A \cup B )$,
\item $\mathrm { P } \left( A ^ { \prime } \cap B \right)$,
\item $\mathrm { P } \left( A \mid B ^ { \prime } \right)$.
\end{enumerate}

\hfill \mbox{\textit{Edexcel S1  Q2 [7]}}